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aliya0001 [1]
4 years ago
9

In a capillary tube, how do we tell which side of the meniscus has higher or lower pressure

Chemistry
1 answer:
galina1969 [7]4 years ago
6 0

Answer:

A liquid with a sharp contact angle (e.g., water on glass) will form a concave meniscus, and the liquid pressure under the meniscus will be smaller than the atmospheric pressure

Explanation:

The phenomenon of capillarity is produced by the action of the surface tension of the fluids and is observed when a small diameter tube is immersed within the fluid. If we pay attention to the result, we can see that, depending on the fluid, two different things can happen, that the liquid rises through the tube and that the level inside the tube is greater than that of the liquid or that the opposite happens.

The case in which the liquid rises above the tube occurs when the liquid "wets". This occurs when the adhesion forces with the walls exceed those of cohesion between the fluid molecules. In this case, the concave side is out of the fluid.

The case where the level of the liquid inside the tube is lower than the level of the liquid occurs when the liquid does not get wet. We remember that the liquid does not get wet when the cohesion forces are greater than those of adhesion. This phenomenon is called capillary depression and the concave angle is for the liquid side and is said to be convex.

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If it took the motorcycle 2 hours to cover 20km, then the average speed is 10km per hour.

Explanation:

Speed is equal to distance over time. So 20km divided by 2 hours is 10 km per hour.

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What is the value of the specific heat capacity of liquid water in j/mol·°c?
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3 years ago
citric acid has an acid dissociation constant of 8.4 x 10^-4 it would be most effective for preparation of a buffer with a pH of
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(B) 3

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pH=pKa+log\frac{[base]}{[acid]}

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3 Mg + 1 Fe2O3 --&gt; 2 Fe + 3 MgO
Gala2k [10]

Answer:

Fe₂O₃ is the limiting reactant.

7.57 g of MgO are formed.

Explanation:

  • 3 Mg + 1 Fe₂O₃ → 2 Fe + 3 MgO

First we <u>convert the given masses of both reactants into moles</u>, using their <em>respective molar masses</em>:

  • 15.6 g Mg ÷ 24.305 g/mol = 0.642 mol Mg
  • 10.0 g Fe₂O₃ ÷ 159.69 g/mol = 0.0626 mol Fe₂O₃

0.0626 moles of Fe₂O₃ would react completely with (3 * 0.0626 ) 0.188 moles of Mg. As there are more Mg moles than required, Mg is the reactant in excess; thus, <em>Fe₂O₃ is the limiting reactant</em>.

We now <u>calculate how many MgO moles are produced</u>, using the <em>number of moles of the limiting reactant</em>:

  • 0.0626 mol Fe₂O₃ * \frac{3molMgO}{1molFe_2O_3} = 0.188 mol MgO

Finally we <u>convert moles of MgO into grams</u>:

  • 0.188 mol MgO * 40.3 g/mol = 7.57 g
8 0
3 years ago
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