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Jobisdone [24]
3 years ago
5

You toss a bowling ball straight up into the air with a speed of 2.1 m/s. How long does it take the bowling ball to reach its hi

ghest point?
Physics
1 answer:
lara [203]3 years ago
6 0

Time taken by the bowling ball to reach its highest point= 0.214 s

initial velocity= Vi=2.1 m/s

Final velocity= Vf=0 as the velocity at the highest point is zero.

acceleration= g= -9.8 m/s²

using the kinematic equation Vf= Vi + at

0= 2.1 + (-9.8)t

t= -2.1/-9.8

t=0.214 s

Thus the time taken by the bowling ball to reach its highest point is 0.214 s

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A lion has a mass of 45 kg. Answer the following questions about it, using correct units. a. The lion runs at a speed of 14.2 m/
Eva8 [605]
A) The kinetic energy of an object is given by:
K= \frac{1}{2}mv^2
where m is the mass of the object, and v its speed. For the lion in our problem, m=45 kg and v=14.2 m/s, so its kinetic energy is
K= \frac{1}{2}mv^2= \frac{1}{2}(45 kg)(14.2 m/s)^2=4537 J

b) the increase in gravitational potential energy of the lion is given by:
\Delta U = mg \Delta h
where g is the gravitational acceleration, and \Delta h is the increase in altitude of the lion. In this problem, \Delta h=28 m, so the increase in gravitational potential energy is
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c) When the fox reaches the top of the tree, its gravitational potential energy is
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6 0
3 years ago
What linear speed must an earth satellite have to be in a circular orbit at an altitude of 159 km?
IgorLugansk [536]
Gravitational acceleration, g = GM/r^2. Additionally, for a satellite in a circular orbit, g = v^2/r

Where, G = Gravitational constant, M = Mass of earth, r = distance from the center of the earth to the satellite, v = linear speed of the satellite.

Equating the two expressions;
v^2/r = GM/r^2
v = Sqrt (GM/r);
But GM = Constant = 398600.5 km^3/sec^2
r = Altitude+Radius of the earth = 159+6371 = 6530 km

Substituting;
v = Sqrt (398600.5/6530) = 7.81 km/sec = 781 m/s
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3 years ago
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Amiraneli [1.4K]
If the velocity of the train is v=s/t, where s is the distance and t is time, then v=400/5=80m/s. To get the vertical component of the velocity we need to multiply the velocity v with a sin(α): Vv=v*sin(α), where Vv is the vertical component of the velocity and α is the angle with the horizontal. So:

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So the vertical component of the velocity of the train is Vv=13.888 m/s.
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