Question

An optical disk drive in your computer can spin a disk up to 10,000 rpm (about 1045 rad/s 1045 rad/s ). If a particular disk is spun at 968.7 rad/s 968.7 rad/s while it is being read, and then is allowed to come to rest over 0.234 seconds 0.234 seconds , what is the magnitude of the average angular acceleration of the disk?

Answer 1

Answer:

The magnitude of the average angular acceleration of the disk is $4139.74\ rad/s^2$.

Explanation:

Given that,

Angular velocity, $\omega_i=968.7\ rad/s$

The disk comes to rest, $\omega_i=0$

Time, t = 0.234 s

We need to find the magnitude of the average angular acceleration of the disk. It is given by change in angular velocity per unit time. So,

$\alpha =\dfrac{\omega f}{t}\\\\\alpha =\dfrac{968.7\ rad/s}{0.234\ s}\\\\\alpha =4139.74\ rad/s^2$

So, the magnitude of the average angular acceleration of the disk is $4139.74\ rad/s^2$.