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nadezda [96]
2 years ago
6

An optical disk drive in your computer can spin a disk up to 10,000 rpm (about 1045 rad/s 1045 rad/s ). If a particular disk is

spun at 968.7 rad/s 968.7 rad/s while it is being read, and then is allowed to come to rest over 0.234 seconds 0.234 seconds , what is the magnitude of the average angular acceleration of the disk?
Physics
1 answer:
Scilla [17]2 years ago
5 0

Answer:

The magnitude of the average angular acceleration of the disk is 4139.74\ rad/s^2.

Explanation:

Given that,

Angular velocity, \omega_i=968.7\ rad/s

The disk comes to rest, \omega_i=0

Time, t = 0.234 s

We need to find the magnitude of the average angular acceleration of the disk. It is given by change in angular velocity per unit time. So,

\alpha =\dfrac{\omega f}{t}\\\\\alpha =\dfrac{968.7\ rad/s}{0.234\ s}\\\\\alpha =4139.74\ rad/s^2

So, the magnitude of the average angular acceleration of the disk is 4139.74\ rad/s^2.

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a projectile is launched straight up at 141 m/s . How fast is it moving at the top of its trajectory? suppose it is launched upw
BARSIC [14]

The velocity of projectile has 2 components, horizontal component vcosθ and vertical component vsinθ, where v is the velocity of projection and θ is the angle between +ve X-axis and projectile motion.

In case 1, θ = 90⁰

    So horizontal component is vcos90 = 0

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So velocity at maximum height = 0 m/s


In case 2, θ = 45⁰

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So velocity at maximum height = 100 m/s


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3 years ago
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kodGreya [7K]

Answer:

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Explanation:

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The sound waves are longitudinal waves that move or travel through different mediums like air, solid, or gas. The waves create vibration in the particles.

You could create a paper cup telephone but instead of using string, test out different materials and see if those materials will allow sound vibrations to travel through them

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3 years ago
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