1) 20 min = 1/3 h
2) distance = speed * time = 12 * 1/3 = 4 km
The speed that the person needs to leave the ground will be 4.32m/s
From the question given,
Height = 95cm
Since the person leave the ground v = 0m/s
acceleration due to gravity g = 9.8m/s²
Using the equation of motion
v² = u² + 2as
a = -g (upward motion)
s = h (distance changes to height)
The equation will become:
0² = u² - 2gh
0² = u² - 2(9.8)(0.95)
u² = 18.62
u = √18.62
u = 4.32
Hence the speed that the person needs to leave the ground will be 4.32m/s
Learn more here: brainly.com/question/20352766
Answer:
The primary reason of seeing the cracker burst and hearing the sound later is because the speed of sound and light. Speed of light is in the vicinity of 3*10^8m,/ sec while the speed of sound is at a distance of 332m/sec. It is similar to lightning that strikes before the sound.
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The concept of Archimedes' principle is that an object immersed in a fluid is buoyed up by a force equal to the weight of the fluid displaced by the object. The fluid displaced has a weight W = mg, where g is acceleration due to gravity. Therefore, the weight of the displaced fluid can be expressed as W = ρVg.
By conservation of momentum,
Pinitial = Pfinal
m1v1 + m2v2 = (m1 + m2)*vf
m1 = mass of skateboard = 1.13 kg
m2 = mass of cat = 0.93 kg
v1 = initial velocity of skateboard = 4.28 m/s
v2 = initial velocity of cat = 0 m/s
vf = final velocity of skateboard-cat combo
So plug in the values and solve for vf,
1.13(4.28) + 0.93(0) = (1.13 + 0.93)vf
vf = 2.35 m/s
