Answer:
A.The vertical velocity is constantly increasing as the ball falls.
B.The horizontal velocity does not noticeably change as the ball falls.
G.The horizontal velocity does not affect how long it will take the ball to fall to the floor.
H.The velocity vector of the ball changes as it travels through the air.
Explanation:
As the ball is projected horizontally so here the vertical component of the velocity is zero
So the time to reach the ground is given as
![H = \frac{1}{2} gt^2](https://tex.z-dn.net/?f=H%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20gt%5E2)
so we will have
![t = \sqrt{\frac{2H}{g}}](https://tex.z-dn.net/?f=t%20%3D%20%5Csqrt%7B%5Cfrac%7B2H%7D%7Bg%7D%7D)
so this is the same time as the ball is dropped from H height
Since there is no force in horizontal direction so its horizontal velocity will always remain constant while vertical velocity will change at constant rate which is equal to acceleration due to gravity.
So overall the velocity vector will change due to net acceleration g
Answer:
you would expect a change in the graph
Explanation:
Answer:
The correct answer is:
(a) 84.240 kg
(b) 24.038 m
Explanation:
The given values are:
Force,
F = 81.0 N
Distance,
S = 13.0 m
Time,
t = 5.20 s
As we know,
The acceleration of mass will be:
⇒ ![a=\frac{2S}{t^2}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B2S%7D%7Bt%5E2%7D)
On substituting the given values, we get
⇒ ![=\frac{2\times 13.0}{(5.20)^2}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B2%5Ctimes%2013.0%7D%7B%285.20%29%5E2%7D)
⇒ ![=\frac{26}{27.04}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B26%7D%7B27.04%7D)
⇒ ![=0.961538 \ m/s^2](https://tex.z-dn.net/?f=%3D0.961538%20%5C%20m%2Fs%5E2)
(a)
The mass of the block will be:
⇒ ![m=\frac{F}{a}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7BF%7D%7Ba%7D)
On substituting the given values, we get
⇒ ![=\frac{81.0}{0.961538}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B81.0%7D%7B0.961538%7D)
⇒ ![=84.240 \ kg](https://tex.z-dn.net/?f=%3D84.240%20%5C%20kg)
(b)
The final velocity after a given time i.e.,
t = 5.00 s
⇒ ![v=at](https://tex.z-dn.net/?f=v%3Dat)
On substituting the values, we get
⇒ ![=0.961538\times 5.00](https://tex.z-dn.net/?f=%3D0.961538%5Ctimes%205.00)
⇒ ![=4.8076 \ m/s](https://tex.z-dn.net/?f=%3D4.8076%20%5C%20m%2Fs)
In time, t = 5.00 s
The distance moved by the block will be:
⇒ ![d=vt](https://tex.z-dn.net/?f=d%3Dvt)
On putting the values, we get
⇒ ![=4.8076\times 5.00](https://tex.z-dn.net/?f=%3D4.8076%5Ctimes%205.00)
⇒ ![=24.038 \ m](https://tex.z-dn.net/?f=%3D24.038%20%5C%20m)
Answer:
The formula for calculating Density is:
= Mass / Volume
From this formula, we can say that the relationship between Mass and Density is a direct one. In other words, if mass is increasing - all else being equal - then density will increase as well.
If mass however was decreasing, density would have to decrease as well.
For example, assume 3 bricks have masses of 5kg, 10kg and 15kg. Also assume that the bricks all have the same volume of 5 m³.
Density of 5kg brick = 5 / 5 = 1 kg/m³
Density of 10kg brick = 10 / 5 = 2kg / m³
Density of 15kg brick = 15 / 5 = 3 kg /m³
<em>Notice how density increases as mass increases and decreases when mass decreases. </em>