Answer
given,
mass of the astronaut = 66 kg
height of the lift = 15 m
acceleration = g/11 = 0.89 m/s²
a) the work done by helicopter
W = F× h
= m (a+g)h
= 66 × (9.8+0.89)15
W =10583.1 J
b) work done by the gravity
W= mgh
W = - 66 × 9.8 × 15
W = -9702 J
c) Δ KE = net work done
Δ KE = 10583.1 - 9702
Δ KE = 881.1 J
d) speed
v =5.17 m/s
Answer: Pretty sure the answer is B but this kind of looks like a test question.
Explanation:
The capacitance of a parallel-plate capacitor in vacuum is given by
where
A is the area of each plate
d is the separation between the plates
is the electric permittivity in vacuum
For the capacitor in our problem, the plates are circular, with a diameter of d=4.0 cm, so their radius is r=2.0 cm=0.02 m and their area is
while the separation between the plates is
Therefore the capacitance is
Answer:
20 pound object
Explanation:
because it is closer to the ground and even though its lighter it is still that one