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Stella [2.4K]
3 years ago
8

A 2.03 cm high insect is 1.39 m from a 131 mm focal-length lens. Where is the image? How high is it?

Physics
1 answer:
ryzh [129]3 years ago
4 0

Answer:

image is 14.47 cm behind the lens

height is 2.11 mm

Explanation:

Given data

h  = 2.03 cm

p = 1.39 m = 139 cm

focal-length f = 131 mm = 13.1 cm

to find out

Where is the image and How high is it

solution

we know focal length formula that is

1/f = 1/p + 1/q

put here value to find q

1/ 13.1 = 1/ 139  + 1 solbe/ q

q =  14.463066 cm

so image is 14.47 cm behind the lens

and

height is calculate

height / h  = - q / p

put here all value

height = -14.47 / 139 × 2.03

height = −0.211324 cm

here -ve sign show image is inverted

so height is 2.11 mm

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Given:

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Now,

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Now, using eqn (1), we get:

\frac{v_{b}}{v_{a}} = \frac{\rho_{a}}{\rho_{b}}

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5 0
3 years ago
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Answer:

The position on the x axis is 0.32 m.

Explanation:

Given that,

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Put the value into the formula

\dfrac{27\times10^{-9}}{x^2}=\dfrac{6\times10^{-9}}{(1-x)^2}

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\dfrac{1-x}{x}=\sqrt{\dfrac{27}{6}}

\dfrac{1}{x}=\sqrt{\dfrac{27}{6}}+1

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Sean climbs a tower that is 71.3 m high to make a jump with a parachute. The mass of Sean plus the parachute is 81.4 kg. If U =
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Answer:

U = 56877.4 J

Explanation:

The potential energy of a body is that which it possesses because it is located at a certain height above the surface of the earth and can be calculated using the following formula:

U = mgh Formula (1)

Where:

U is the potential energy in Joules (J)

m is the mass of the body in kilograms (kg)

g is the acceleration due to gravity (m/s²)

h is the height at which the body is found from the surface of the earth in meters (m)

Data

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We replace data in the formula (1)

U = m*g*h

U = (81.4 kg)*(9.8 m/s²)*(71.3 m)

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