<span> you divide the radius of the </span>wheel<span> by the radius of the </span>axle<span>.</span>
The question looks incomplete, but according to the information given above seem like they have <span>identical journeys.
</span>a. the displacement of car A - <span> 65.5 m
</span>b. the displacement of car B - <span>65.5 m
c. average velocir</span>y of A

d. the average velocity of car B has the same.
Answer:
-0.1875 V.
Explanation:
Using
E₂ = MdI₁/dt........................ Equation 1
Where E₂ = Voltage induced in the second coil, M = mutual inductance of both coil, dI₁ = change in current in the first coil, dt = change in time.
Given: M = 3.00 mH = 0.003 H, dI₁ = (0-2.50) = -2.5 A, dt = 40 ms = 0.04 s.
Substitute into equation 1
E₂ = 0.003(-2.5)/0.04
E₂ = -0.1875 V.
Hence the induced emf = -0.1875 V.
False
Because you can see using a thermal camera I guess