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Stella [2.4K]
3 years ago
8

A 2.03 cm high insect is 1.39 m from a 131 mm focal-length lens. Where is the image? How high is it?

Physics
1 answer:
ryzh [129]3 years ago
4 0

Answer:

image is 14.47 cm behind the lens

height is 2.11 mm

Explanation:

Given data

h  = 2.03 cm

p = 1.39 m = 139 cm

focal-length f = 131 mm = 13.1 cm

to find out

Where is the image and How high is it

solution

we know focal length formula that is

1/f = 1/p + 1/q

put here value to find q

1/ 13.1 = 1/ 139  + 1 solbe/ q

q =  14.463066 cm

so image is 14.47 cm behind the lens

and

height is calculate

height / h  = - q / p

put here all value

height = -14.47 / 139 × 2.03

height = −0.211324 cm

here -ve sign show image is inverted

so height is 2.11 mm

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2 years ago
A horizontal force of 92.7 N is applied to a 40.5 kg crate on a rough, level surface. If the crate accelerates at 1.13 m/s2, wha
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Answer:

The value is F_f =  46.935 \  N

Explanation:

From the question we are told that

    The  magnitude of the horizontal force is F  =  92.7 \  N

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     The acceleration of the crate is  a =  1.13 \ m/s

Generally the net force acting on the crate is mathematically represented as

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Here F_f is force of kinetic friction (in N) acting on the crate

      So  

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3 years ago
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Answer:

3.2075*10^16

Explanation:

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8 0
3 years ago
Read 2 more answers
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