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damaskus [11]
3 years ago
6

Newton's First Law is:

Physics
1 answer:
Reptile [31]3 years ago
6 0

Answer:

it's option 2

Explanation:

Newton's first law states that, if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force

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Choose all the answers that apply. The sun: -is the largest star in our solar system -is the largest star in our galaxy
Hatshy [7]

-is made mostly of hydrogen and helium.

-will eventually run out of fuel and die.

-creates energy through nuclear reactions

8 0
3 years ago
Read 2 more answers
Upper A 12​-pound box sits at rest on a horizontal​ surface, and there is friction between the box and the surface. One side of
Maurinko [17]

Answer:

The coefficient of static friction is : 0.36397

Explanation:

When we have a box on a ramp of angle \alpha , and the box is not sliding because of friction, one analyses the acting forces in a coordinate system system with an axis parallel to the incline.

In such system, the force of gravity acting down the incline is the product of the box's weight times the sine of the angle:

F_g=W\,*\, sin(\alpha)\\F_g=m*g\,*\, sin(\alpha)

Recall as well that component of the box's weight that contributes to the Normal N (component perpendicular to the ramp) is given by:

N=m*g*cos(\alpha)

and the force of static friction (f) is given as the static coefficient of friction (\mu) times the normal N:

f=\mu *m*g*cos(\alpha)

When the box starts to move, we have that the force of static friction equals this component of the gravity force along the ramp:

f=F_g\\\mu *\,m*g*cos(\alpha)=m*g\,*\, sin(\alpha)

Now we use this last equation to solve for the coefficient of static friction, recalling that the angle at which the box starts moving is 20 degrees:

\mu *\,m*g*cos(\alpha)=m*g\,*\, sin(\alpha)\\\mu=\frac{sin(\alpha)}{cos(\alpha)}\\\mu = tan(\alpha)\\\mu=tan(20^o)\\\mu=0.36397

6 0
3 years ago
Explain why a Merry-Go-Round and a Ferris Wheel have a constant acceleration when they are moving.
luda_lava [24]

Explanation:What is centripetal acceleration?

Can an object accelerate if it's moving with constant speed? Yup! Many people find this counter-intuitive at first because they forget that changes in the direction of motion of an object—even if the object is maintaining a constant speed—still count as acceleration.

Acceleration is a change in velocity, either in its magnitude—i.e., speed—or in its direction, or both. In uniform circular motion, the direction of the velocity changes constantly, so there is always an associated acceleration, even though the speed might be constant. You experience this acceleration yourself when you turn a corner in your car—if you hold the wheel steady during a turn and move at constant speed, you are in uniform circular motion. What you notice is a sideways acceleration because you and the car are changing direction. The sharper the curve and the greater your speed, the more noticeable this acceleration will become. In this section we'll examine the direction and magnitude of that acceleration.

The figure below shows an object moving in a circular path at constant speed. The direction of the instantaneous velocity is shown at two points along the path. Acceleration is in the direction of the change in velocity, which points directly toward the center of rotation—the center of the circular path. This direction is shown with the vector diagram in the figure. We call the acceleration of an object moving in uniform circular motion—resulting from a net external force—the centripetal acceleration

a

c

a

c

​

a, start subscript, c, end subscript; centripetal means “toward the center” or “center seeking”.

5 0
4 years ago
Identify and draw the forces that act on the pencil. Be certain to draw each force at the correct location (the point at which t
Alekssandra [29.7K]

Answer:

Explanation:

find solution below

6 0
4 years ago
Magnitude of force F experienced by a certain object moving with speed v is given by F=Kv race to 2, where K is constant. Find t
My name is Ann [436]
<h2>Answer:</h2>

MT⁻¹

<h2>Explanation:</h2>

Given equation:

F = Kv        --------------(i)

Where;

F = Magnitude of force experienced by the object

v = speed at which the object is moving

K = constant.

To get the dimension of K, follow the following steps:

i. <em>Make K subject of the formula in equation(i)</em>

K = F / v

ii.<em> Get the dimension of force F and speed v</em>

Dimension of force = MLT⁻²

Dimension of velocity = LT⁻¹

iii.<em> Substitute these dimensions into the result of (i) above;</em>

K = MLT⁻² / LT⁻¹

iv. <em>Simplify the result in (iii)</em>

<em>First, the </em><em>L</em><em>s in the numerator and denominator will cancel out</em>

K = MT⁻² / T⁻¹

<em>Next, the </em><em>T</em><em>s will be expressed as follows</em>

K = MT⁻² x T¹           [using the law of indices]

K = MT⁻²⁺¹

K = MT⁻¹

Therefore, the dimension of K is MT⁻¹

6 0
3 years ago
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