The magnitude of the magnetic dipole moment of the bar magnet is 1.2 Am²
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Magnetic dipole moment of the bar magnet</h3>
The magnitude of the magnetic dipole moment of the bar magnet at distance from its axis is calculated as follows;

where;
- B is magnetic field
- m is dipole moment
- μ is permeability of free space
m = (4π x 0.1³ x 2.4 x 10⁻⁴)/(2 x 4π x 10⁻⁷)
m = 1.2 Am²
The complete question is below:
What is the magnitude of the magnetic dipole moment of the bar magnet from 0.1 m of its axis and magnetic field strength of 2.4 x 10⁻⁴ T.
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Answer:
Explanation:
Conclusion is simple you can just say that it is the value written in words form only.
Nothing else is written about it
Work = force x distance
200 Newtons x 20 meters
= 4,000 Joules
S.I. Unit of mass is Kilogram which is denoted by Kg
In short, Your Answer would be Option C
Hope this helps!