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3 years ago

Hello I need help its due today!

1 answer:

5 0

Answer:This also means that Mercury's surface gravity is 3.7 m/s2, which is the equivalent of 38% of Earth's gravity (0.38 g). This means that if you weighed 100 kg (220 lbs) on Earth, you would weigh 38 kg (84 lbs) on Mercury.

Explanation:

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What is the speed over the ground of a mosquito flying 2 m/s relative to the air against a 2 m/s headwind?

salantis [7]

We have that the speed over the ground of a mosquito flying 2 m/s relative to the air against a 2 m/s headwind is

X=0m/s

From the question we are told that

mosquito flying 2 m/s

against a 2 m/s headwind

Generally

The speed over the ground is the Flight Speed minus resistance speed

Generally the equation for the speed over the ground is mathematically given as

X=Flight Speed-resistance speed

Therefore

X=2-2

X=0m/s

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8 0

3 years ago

Read 2 more answers

Suppose you buy some inflated party balloons that are at room temperature (about 20°C). What will happen to those balloons if yo

Zina [86]

The balloons will begin to shrink or deflate.

7 0

3 years ago

A 65 Kg roller-blade is accelerating at 5 m/s/s across the side walk. What force would be necessary for this acceleration to occ

Neporo4naja [7]

Newton's second law states that the force applied to an object is equal to the product between the mass m of the object and its acceleration a:
$F=ma$
Using $m=65 kg$ and $a=5 m/s^2$ , we can find the value of the force applied to the roller-blade to obtain this acceleration:
$F=(65 kg)(5 m/s^2)=325 N$

3 0

3 years ago

While goofing off at the ice skating rink, a student takes off her shoes and places each of them on the ice. Her friend, a hocke

sukhopar [10]

Answer:

Right shoe

Explanation:

Let the mass and velocity of incoming puck be m and v respectively.

Momentum of the colliding puck will be mv

In case of first case , the momentum of puck becomes zero so change in momentum after collision with left shoe

= mv - 0 = mv

If time duration of collision be t

rate of change of momentum

= mv / t

This is the force exerted by puck on the left shoe .

Now let us consider collision with right shoe

momentum after collision with right shoe

- mv

change in momentum

= mv - ( - mv ) = 2mv

If time duration of collision be t

rate of change of momentum

= 2mv / t

This is the force exerted by puck on the right shoe .

Since the force on the right shoe is more , this shoe will have greater speed

after collision.

6 0

3 years ago

In a physics laboratory experiment, a coil with 250 turns enclosing an area of 10.5 cm2 is rotated during the time interval 3.10

olchik [2.2K]

I guess the problem is asking for the induced emf in the coil.

Faraday-Neumann-Lenz states that the induced emf in a coil is given by:
$\epsilon = -N \frac{\Delta \Phi}{\Delta t}$
where
N is the number of turns in the coil
$\Delta \Phi$ is the variation of magnetic flux through the coil
$\Delta t$ is the time interval

The coil is initially perpendicular to the Earth's magnetic field, so the initial flux through it is given by the product between the magnetic field strength and the area of the coil:
$\Phi_i = BA=(5.30 \cdot 10^{-5}T)(10.5 \cdot 10^{-4} m^2)=5.57 \cdot 10^{-8} Wb$
At the end of the time interval, the coil is parallel to the field, so the final flux is zero:
$\Phi_f = 0$

Therefore, we can calculate now the induced emf by using the first formula:
$\epsilon = -N \frac{\Delta \Phi}{\Delta t}=- (250) \frac{5.57 \cdot 10^{-8} Wb - 0}{3.10 \cdot 10^{-2} s} = -4.5 \cdot 10^{-4} V$

7 0

4 years ago