Question

-Two pickup trucks each have a mass of 2,000 kg. The gravitational force between the

Answer 1

Answer:

$F'=4.5\times 10^{-5}\ N$

Explanation:

The gravitational force between two pickups is given by :

$F=G\dfrac{m_1m_2}{r^2}$

It means,

$F\propto m_1m_2$

So,

$\dfrac{F}{F'}=\dfrac{m_1m_2}{m_1'm_2'}$

We have,

$m_1=m_2=2000\ kg\\\\F=3\times 10^{-5}\ N\\\\m_1'=2000+1000 =3000\ kg\\\\m_2'\ \text{remains the same i.e. 1000 kg}$

F' is the new force

So, putting all the values,

$\dfrac{3\times 10^{-5}}{F'}=\dfrac{2000\times 2000}{3000\times 2000}\\\\\dfrac{3\times 10^{-5}}{F'}=\dfrac{2}{3}\\\\F'=\dfrac{9\times 10^{-5}}{2}\\\\F'=4.5\times 10^{-5}\ N$

So, the new force between the two trucks is $4.5\times 10^{-5}\ N$.