Question 14 (1 point)

If you stood on mars and lifted a 15kg pack, you would be pulling with a force greater than...?

DIA [1.3K]

Answer:

See the answers below

Explanation:

In this problem, we must be clear about the concept of weight. Weight is defined as the product of mass by gravitational acceleration.

We must be clear that the mass is always preserved, that is, the mass of 15 [kg] will always be the same regardless of the planet where they are.

$W=m*g$

where:

W = weight [N] (units of Newtons)

m = mass = 15 [kg]

g = gravity acceleration [m/s²]

Since we have 9 places with different gravitational acceleration, then we calculate the weight in each of these nine places.

Mercury

$w_{mercury} = 15*3.8\\w_{mercury}= 57 [N]\\$

Venus

$w_{venus}=15*8.8\\w_{venus}= 132 [N]$

Moon

$w_{moon}=15*1.6\\w_{moon}=24[N]$

Mars

$w_{mars}=15*3.7\\w_{mars}=55.5 [N]$

Jupiter

$w_{jupiter}=15*23.1\\w_{jupiter}= 346.5[N]$

Saturn

$w_{saturn}=15*9\\w_{saturn}=135[N]$

Uranus

$w_{uranus}=15*8.7\\w_{uranus}=130.5[N]$

Neptune

$w_{neptune}=15*11\\w_{neptune}=165[N]$

Pluto

$w_{pluto}=15*0.6\\w_{pluto}=9[N]$

7 0

2 years ago

A tennis ball is tossed upwards into the air with an initial velocity of +5m/s, how much time does it take for the tennis ball t

Sever21 [200]

HOPE THIS HELPS YOU!!!!!

3 0

3 years ago

Two trains are traveling on the same track and in the same direction. The first train, which is behind the second train, blows a

Andrews [41]

Answer:

37.545 m/s

Explanation:

f' = Actual frequency of horn = 269 Hz

f = Observed frequency of horn = 290 Hz

v = Speed of sound in air = 343 m/s

$v_0$ = Speed of second train = 13.7 m/s

$v_s$ = Speed of first train

From Doppler effect we have

$f=f'\dfrac{v-v_0}{v-v_s}\\\Rightarrow v_s=v-\dfrac{f'}{f}(v-v_0)\\\Rightarrow v_s=343-\dfrac{269}{290}(343-13.7)\\\Rightarrow v_s=37.545\ m/s$

The speed of the first train is 37.545 m/s

5 0

3 years ago

Hi! Can somebody please help?

dezoksy [38]

Answer:

Diagram A will reach the top first.

Explanation:

If it is going straight, it will go slower. The higher the movement speed the faster it is. Hope this helps!

7 0

3 years ago

"The International Space Station (ISS) orbits at a distance of 350 km above the surface of the Earth. (a) Determine the gravitat

vagabundo [1.1K]

Answer:

(a) g = 8.82158145 $m/s^2$ .

(b) 7699.990192m/s.

(c)5484.3301s = 1.5234 hours.(extremely fast).

Explanation:

(a) Strength of gravitational field 'g' by definition is

$g = \frac{M_{(earth)} }{r^2} G$ , here G is Gravitational Constant, and r is distance from center of earth, all the values will remain same except r which will be radius of earth + altitude at which ISS is in orbit.

r = 6721,000 meters, putting this value in above equation gives g = 8.82158145 $m/s^2$ .

(b) We have to essentially calculate centripetal acceleration that equals new 'g'.

$a_{centripetal}=\frac{V^2}{r} =g$ here g is known, r is known and v is unknown.

plugging in r and g in above and solving for unknown gives V = 7699.990192m/s.

(c) S = vT, here T is time period or time required to complete one full revolution.

S = earth's circumfrence , V is calculated in (B) T is unknown.

solving for unknown gives T = 5484.3301s = 1.5234hours.

3 0

3 years ago