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ipn [44]
3 years ago
11

_____ help by supporting the plant and holding the leaves up to the light.

Physics
2 answers:
Semenov [28]3 years ago
7 0
The answer is the stem.
pochemuha3 years ago
3 0

Answer:

The Answer is Stem :D

Explanation:

Because the stem is the part that holds the plant to the light.

Hope i helped

and again the answer is the stem.. :D

Have a great day!!

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A stone is thrown horizontally from the top of a tower at the same instant a ball is droppedvertically. Which object is travelin
Igoryamba

The ball is travelling faster when the two objects hits the level ground below.

<h3>Time of motion of the objects</h3>

The time of motion of the objects depends on height and initial velocity of projection of the objects.

The stone has no initial vertical velocity while the ball has initial vertical velocity.

Thus, the ball is travelling faster when the two objects hits the level ground below.

Learn more about time of motion here: brainly.com/question/2364404

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5 0
2 years ago
A wheel of mass 60.0 kg is pushed with a net force of 26.4 N. Find acceleration.
worty [1.4K]

F= ma; a= F/m

a = 26.4 N/60 kg= 0.44 m/s^2

4 0
3 years ago
Kinetic energy of an object is equal to
Gnom [1K]
See
K.E=1/2(mass*velocity²)
so option B is the correct answer.
Brainliest pls :-)
8 0
3 years ago
The speed of sound in wood is ____ the speed of sound in water.
pishuonlain [190]

Answer:

greater

Explanation:

the speed of sound in steel is greater than water. the speed of sound in wood is not, In water, the particles are much closer together, and they can quickly transmit vibration energy from one particle to the next. This means that the sound wave travels over four times faster than it would in air, but it takes a lot of energy to start the vibration.

Wood is less dense and force can make a sound.

8 0
3 years ago
A 49.0 kg wheel, essentially a thin hoop with radius 0.730 m, is rotating at 114 rev/min. It must be brought to a stop in 22.0 s
belka [17]

Explanation:

Mass of the wheel, m = 49 kg

Radius of the hoop, r = 0.73 m

Initial angular speed of the wheel, \omega_i=114\ rev/min = 11.93\ rad/s

Final angular speed of the wheel, \omega_f=0

Time, t = 22 s

(a) If I is the moment of inertia of the hoop. It is equal to,

I=mr^2

I=49\times (0.73)^2

I=26.11\ kg-m^2

We know that the work done is equal to change in kinetic energy.

W=\Delta E

W=\dfrac{1}{2}I(\omega_f^2-\omega_i^2)

W=-\dfrac{1}{2}\times 26.11\times (11.93^2)

W = -1858.05 Joules

(b) Let P is the average power. It is given by :

P=\dfrac{W}{t}

P=\dfrac{1858.05\ J}{22\ s}

P =84.45 watts

Hence, this is the required solution.

4 0
3 years ago
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