Good morning.
We see that

The magnitude(norm, to be precise) can be calculated the following way:

Now the calculus is trivial:
Answer:
Because psuedoscience is a collection of beliefs or practices mistakenly regarded as being based on scientific method.
And it is most of the time false
Explanation:
a toy/model steam engine. how it works and how to measure horse power
.Answer:
The value of the work done is
.
Explanation:
When a charged particle having charge
is moving through an electric field
, the net force (
) on the charge is

and the work done (
) by the particle is

Given,
.
Substitute the value of electric field in equation (1) and then substitute the result in equation (2).
![W &=& \int\limits^7_0 {q\dfrac{A_{0}}{x^{1/2}}} \, dx \\&=& qA_{0} \int\limits^7_0 {x^{-1/2}} \, dx \\&=& 2qA_{0}[x^{1/2}]_{0}^{7}\\&=& 5.29 qA_{0}](https://tex.z-dn.net/?f=W%20%26%3D%26%20%5Cint%5Climits%5E7_0%20%7Bq%5Cdfrac%7BA_%7B0%7D%7D%7Bx%5E%7B1%2F2%7D%7D%7D%20%5C%2C%20dx%20%5C%5C%26%3D%26%20qA_%7B0%7D%20%5Cint%5Climits%5E7_0%20%7Bx%5E%7B-1%2F2%7D%7D%20%5C%2C%20dx%20%5C%5C%26%3D%26%202qA_%7B0%7D%5Bx%5E%7B1%2F2%7D%5D_%7B0%7D%5E%7B7%7D%5C%5C%26%3D%26%205.29%20qA_%7B0%7D)
Answer:

Explanation:
The x- and y- components of the velocity vector can be written as following:


Since the angle θ and the magnitude of the velocity is given, the vector representation can be written as follows:
