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alexdok [17]
4 years ago
13

A loud speaker inside a room is generating sound that spreads out uniformly in all directions. At a certain location 5 m away fr

om the loud speaker, the sound waves coming directly from the speaker (without reflecting from the walls) create a decibel level of 75.0 dB with respect to the threshold of hearing. (a) What is the power of the loud speaker
Physics
1 answer:
Ahat [919]4 years ago
3 0

Answer:

Explanation:

We shall convert decibel into intensity of sound in Watt / m²

75 decibell = 7.5 bell

7.5 = log ( I / 10⁻¹² )

I / 10⁻¹² = 10⁷°⁵

I = 10⁻¹² x  10⁷°⁵

= 10⁻⁴°⁵ watt / m²

Let power of the loudspeaker be P

intensity of sound 5m away will be given by the formula

P / 4π d² where , d is distance of the point at which intensity is measured

Puting the given values

P /4π 5² = 10⁻⁴°⁵

P = 4π 5² x 10⁻⁴°⁵

= 99.3 x 10⁻⁴ W

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