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yaroslaw [1]
2 years ago
5

Can someone please help me with my chem final!!

Chemistry
1 answer:
scoundrel [369]2 years ago
6 0

Answer:

direct

Explanation:

the more dense it is the more pressure it will exert

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How much energy is required to raise the temperature of a 300.0
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Answer:

Q = 1455.12 Joules.

Explanation:

Given the following data;

Mass = 300 grams

Initial temperature = 22.3

Final temperature = 59.9°C

Specific heat capacity = 0.129 J/gºC.

To find the quantity of energy;

Q = mcdt

Where,

Q represents the heat capacity.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

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dt = 59.9 - 22.3

dt = 37.6°C

Substituting the values into the equation, we have;

Q = 300*0.129*37.6

Q = 1455.12 Joules.

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