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mezya [45]
3 years ago
11

Which of the following molecules is nonpolar?

Chemistry
1 answer:
Rudik [331]3 years ago
7 0

Answer:

1. BF3 This is a trigonal planar molecule; the electron density is drawn into a cloud that circles the Boron, this is made nonpolar by the geometrically equivalent structure of the surrounding electronegative Fluorines.

2. H2O The 2 lone pairs of e- of Oxygen makes the O partially negative, the H’s, partially positive. Polar.

3. NF3 Lone pair on Nitrogen overwhelmed by the 3 incredibly electronegative Fluorines. Polar

4. CH3Br The “Soft Ion” of Bromine is negative; it is electronegative. Polar.

5. SO2 the lone pairs of Oxygen, at approximately 119°-120° angles to one another will form a reasonance structure; there will be more lone pairs about the Oxygen than the Sulfur; the Sulfur will be partially positive compared to the oxygens. Polar.

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What is the mass, in grams, of solute in 255mL of a 0.0525M solution of KMnO4 (MM =
aliya0001 [1]

Answer:

Mass = 2.12 g

Explanation:

Given data:

Volume of KMnO₄ = 255 mL (255/1000 = 0.255 L)

Molarity = 0.0525 M

Mass in gram = ?

Solution:

First of all we will calculate the number of moles.

<em>Molarity = number of moles of solute / volume in litter</em>

0.0525 M = number of moles of solute / 0.255 L

Number of moles of solute = 0.0525 M ×0.255 L

Number of moles of solute = 0.0134 mol

Mass in gram:

<em>Number of moles = mass/ molar mass</em>

Mass = moles × molar mass

Mass = 0.0134 mol × 158.04 g/mol

Mass = 2.12 g

7 0
3 years ago
What do you think a chemical change is?
Rudiy27

Answer:

a chemical change is when the substance turns into a new substance and can not be changed back into its original form

Explanation:

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3 years ago
How is the mass of a compound related to its chemical formula
Monica [59]
They're totally unrelated. No matter how low or high the molecular weight, you can always use more or less of it.
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3 years ago
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Explanation:

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3 years ago
what is the change in the velocity of the biker below as he travels from point b to point c ? ..... What is his acceleration fro
Furkat [3]

The change in the velocity = 4 m/s

Acceleration = 4 m/s²

<h3>Further explanation</h3>

Given

vo = initial velocity = 4 m/s

vf = final velocity = 8 m/s

t = 1 s

Required

The change in the velocity

Acceleration

Solution

the change in velocity =

\tt vf-vo=8-4=4~m/s

Acceleration = ratio of a change in velocity and the time

\tt a=\dfrac{\Delta v}{t}= \dfrac{vf-vo}{t}

Input the value :

\tt a=\dfrac{4~m/s}{1~s}=4~m/s^2

7 0
3 years ago
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