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adelina 88 [10]
3 years ago
15

What element has only one proton in its nucleus??

Chemistry
1 answer:
blagie [28]3 years ago
3 0
Hydrogen is the only element in entire periodic table with only 1 proton in its nucleus.
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The concentration of a biomolecule inside a rod-shaped prokaryotic cell is 0.0029 m. calculate the number of molecules inside th
bagirrra123 [75]
Molarity is expressed as:
Molarity = moles / liter

Given that the cell is rod-shaped, its volume is calculated using the formula for a cylinder's volume:

V = πr²L
V = π * (0.6)² * 4.9
V = 5.54 μm³

1 Liter = 10³ mm³
1 mm = 10³ μm
1 mm³ = 10⁹ μm³
1 liter = 10¹² μm³

So the volume in liters is:
5.54 x 10⁻¹² L

Moles = molarity * liters
Moles = 0.0029 * 5.54 x 10⁻¹²
Moles = 1.61 x 10⁻¹⁴

To get the number of molecules, we multiply the moles by Avagadro's number

Number of molecules = 1.61 x 10⁻¹⁴ * 6.02 x 10²³

There are 9.69 x 10⁹ molecules in the cell
4 0
3 years ago
Match the image with the correct invention
PolarNik [594]

Answer:

1. Watt stream engine

2. McCormick reaper

3. Fulton steamboat

These are the correct answers.

Have A good day!!  :)

8 0
3 years ago
Read 2 more answers
Hydrochloric acid reacts with sodium hydroxide to form water and sodium chloride. Hydrochloric acid is an extremely acidic, clea
olya-2409 [2.1K]

Answer:

I think it is a).

Explanation:

3 0
3 years ago
Urea (CH4N2O) is a common fertilizer that can be synthesized by the reaction of ammonia (NH3) with carbon dioxide as follows: 2N
Montano1993 [528]

The question is incomplete, here is the complete question:

Urea (CH₄N₂O) is a common fertilizer that can be synthesized by the reaction of ammonia (NH₃) with carbon dioxide as follows: 2NH₃(aq) + CO₂(aq) → CH₄N₂O(aq) + H₂O(l) In an industrial synthesis of urea, a chemist combines 135.9 kg of ammonia with 211.4 kg of carbon dioxide and obtains 178.0 kg of urea.

Determine the limiting reactant. (express your answer as a chemical formula)

<u>Answer:</u> The limiting reactant is ammonia (NH_3)

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For ammonia:</u>

Given mass of ammonia = 135.9 kg = 135900 g    (Conversion factor:  1 kg = 1000 g)

Molar mass of ammonia = 17 g/mol

Putting values in equation 1, we get:

\text{Moles of ammonia}=\frac{135900g}{17g/mol}=7994.12mol

  • <u>For carbon dioxide gas:</u>

Given mass of carbon dioxide gas = 211.4 kg = 211400 g

Molar mass of carbon dioxide gas = 44 g/mol

Putting values in equation 1, we get:

\text{Moles of carbon dioxide gas}=\frac{211400g}{44g/mol}=4804.54mol

The given chemical reaction follows:

2NH_3(aq.)+CO_2(aq,)\rightarrow CH_4N_2O(aq.)+H_2O(l)

By Stoichiometry of the reaction:

2 moles of ammonia reacts with 1 mole of carbon dioxide

So, 7994.12 moles of ammonia will react with = \frac{1}{2}\times 7994.12=3997.06mol of carbon dioxide

As, given amount of carbon dioxide is more than the required amount. So, it is considered as an excess reagent.

Thus, ammonia is considered as a limiting reagent because it limits the formation of product.

Hence, the limiting reactant is ammonia (NH_3)

5 0
3 years ago
During a volcanic eruption, large amounts of poisonous gases and particles are released into the atmosphere. How do some of thes
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A through rain because it is:)
3 0
3 years ago
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