We are given the acceleration of the bus as a function of time:
a(t) = 1.2t
Let the velocity also be a function of time v(t).
Since a(t) is the change of v(t) over time, we can use the fundamental theorem of calculus to determine the velocity at t = 2s, or v(2), given that:
a(t) = 1.2t
v(1) = 5
v(2) - v(1) = 
v(2) - 5 = 
v(2) - 5 = 0.6t² evaluated between t = 1 and t = 2
v(2) - 5 = 0.6(4) - 0.6(1)
v(2) = 1.8 + 5
v(2) = 6.8m/s
A is the only answer because
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Acceleration occurs when there is a change in speed or direction. If it travels in a straight line, there is no speed or change in direction as it is constant througout, hence 0 acceleration.
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