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2 years ago

8

What is the KE if a 10kg mass traveling at 5 m/s

1 answer:

11111nata11111 [884]2 years ago

7 0

Answer: KE = 25 J

Explanation: You must use the formula

KE = 1/2 m v²

to solve this problem.

KE = 1/2 (10 Kg) (5 m/s)

KE = 1/2 (50 kgm/s)

KE = 25 J

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7) Sound waves travel with a nominal speed of 340m/s.

Savatey [412]

Answer:

The wavelengths of C1 is 10.4m, A6 is 0.193m and B7 is 0.0861m

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Using the formula V = f×λ . Then substitute the following values into the formula:

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2 years ago

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3 years ago

A heat exchanger is to heat water (cp = 4.18 kJ/kg·°C) from 25 to 60°C at a rate of 0.2 kg/s. The heating is to be accomplished

Rama09 [41]

Answer:

The heat exchanger is 29.26 kJ/s.

The exit temperature of geothermal water is 117.37°C.

Explanation:

Given that,

Specific heat $c_{p}=4.18\ kJ/kg°C$

Initial temperature = 25°C

Final temperature = 60°C

Specific heat by geothermal $c_{p}=4.31\ kJ/kg°C$

Temperature = 140°C

Mass flow rate = 0.3 kg/s

We need to calculate the rate of heat transfer in heat exchange

Using formula of rate of heat transfer in heat exchanger

$Q=\dot{m}c_{p}\Delta T$

Put the value into the formula

$Q=0.2\times4.18\times(60-25)$

$Q=29.26\ kJ/s$

We need to calculate the exit temperature of geothermal water

Heat transferred to feed water= Heat transferred by geothermal water

$0.2\times4.18\times(60-25)=0.3\times4.31\times(140-T_{exit})$

$T_{exit}=\dfrac{29.26-181.02}{1.293}$

$T_{exit}=117.37^{\circ}C$

Hence, The rate of heat exchanger is 29.26 kJ/s.

The exit temperature of geothermal water is 117.37°C.

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3 years ago