Question

Please help!

Answer 1

Answer:

Probability of picking an even and then even number = $\frac{1}{6}$

Step-by-step explanation:

Probability of picking a card with even number,

P(even 1) = $\frac{\text{favorable outcomes}}{\text{Total outcomes}}$ = $\frac{\text{even cards}}{\text{Total number of cards}}$

               = $\frac{2}{4}$

               = $\frac{1}{2}$

Followed by picking a card which is even without putting the first card back.

So an even card is to be picked out of remaining 3 cards.

P(even 2) = $\frac{\text{favorable outcomes}}{\text{Total outcomes}}$

                = $\frac{1}{3}$

Now probability of both events = P(even 1) × P(even 2)

= $\frac{1}{2}\times \frac{1}{3}$

= $\frac{1}{6}$

Therefore, probability of both the events will be $\frac{1}{6}$.