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Evgen [1.6K]
3 years ago
12

Which word is NOT a conjunctive adverb?

Physics
2 answers:
hichkok12 [17]3 years ago
7 0

Answer:

bruh ._. bruh ._. bruh ._. bruh ._. bruh

pochemuha3 years ago
4 0
Because is not an conjunctive adverb
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A stretched string is 2.11 m long and has a mass of 19.5 g. When the string oscillates at 440 Hz , which is the frequency of the
blsea [12.9K]

Answer:

The tension of the string is 41.876 N

Explanation:

Given;

length of the string, L = 2.11 m

mass of the string, m = 19.5 g = 0.0195 kg

frequency of the wave, f = 440 Hz

wavelength, λ = 15.3 cm = 0.153 m

The velocity of the wave is given by;

v = fλ

v = 440 x 0.153

v = 67.32 m/s

Also the velocity of the wave is given by

v = \sqrt{\frac{T}{\mu} }

where;

μ is mass per unit length = 0.0195 / 2.11 = 0.00924 kg/m

T is the tension of the string

T = v²μ

T = (67.32)²(0.00924)

T = 41.876 N

Therefore, the tension of the string is 41.876 N

5 0
4 years ago
Who is famous for having introduced the three laws of motion?
Digiron [165]

Isaac Newton is famous for the three laws

3 0
3 years ago
Read 2 more answers
Cold air holds less water than warm air.<br> True<br> False
Vsevolod [243]

Answer:

The answer is for your question is :

Explanation:

True

4 0
2 years ago
What angle is formed by the sun, the earth, and the moon during an eclipse?.
Andrew [12]

Answer:

The Sun-Earth-Moon system happens to exhibit a striking geometric coincidence, which we examine in the first problem. PROBLEM 1. To an observer on Earth, the Sun and the Moon subtend almost the same angle in the sky. The average angle is 0.52 degrees for the Moon and 0.53 degrees for the Sun.

4 0
3 years ago
In a mass spectrometer, a single-charged particle (charge e) has a speed of 1.0 × 10 6 m/s and enters a uniform magnetic field o
Nonamiya [84]

Answer:

The mass is  m  =6.4*10^{-28} \ kg

Explanation:

From the question we are told that

   The  speed of the charge is  v   = 1.0 *10^{6} \  m/s

    The  magnetic field is  B = 0.20 \ T

     The radius is r  =  0.02 \ m

      The value of the charge is  e  = 1.60 *10^{-19} \  C

The centripetal acting on the charge moving in the circular orbit is mathematically represented as

        F_c  =  \frac{mv^2}{r }

Now this centripetal force is due to the force exerted on the charge by the magnetic field on the charge which is mathematically represented as

     F_m  =  qv  B  sin\theta

At the maximum of this magnetic force \theta =  90 ^o

So  

     F_m  =  e v  B  sin(90)

      F_m  =  e v  B

Now given that it is this  magnetic force that is causing the circular motion we have that

       F_c  =  F_m

=>     \frac{mv^2}{r }  =  ev  B

=>     m  = \frac{e * B  *  r  }{v }

substituting values

       m  = \frac{ 1.60 *10^{-19} *  0.20   *  0.020   }{1.0*10^{6} }

     m  =6.4*10^{-28} \ kg

8 0
4 years ago
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