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Tomtit [17]
3 years ago
5

Barnard’s Star is a red dwarf. It is located 5.9 light years from Earth. (One light year is the same as 9.46 trillion kilometers

.) This distance in kilometers is how many trillion kilometers is it?
Physics
2 answers:
ValentinkaMS [17]3 years ago
8 0

Answer: 55.814 trillion kilometers

Explanation:       \frac{d}{5.9 light\\years}       \frac{9.46 trillion kilometers}{1 light year}

d (1 light year) = 9.46 trillion kilometers (5.9 light years)

d (1) = 9.46 trillion kilometers (5.9)

d = 55.814 trillion kilometers

mote1985 [20]3 years ago
5 0
A star is located 5.9 light years from Earth.
We know that : 1 light year = 9.46  trillion kilometers.
We will calculate the distance in trillion kilometers multiplying the number of light years by 9.46:
5.9 * 9.46 = 55.814
Answer: The distance is 55.814 trillion km.
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An airplane travels 500 miles in 2.5 hours. What is the speed of the plane in mi/sec
prohojiy [21]

Average speed is 0.055miles per sec

3 0
3 years ago
A vehicle hits a bridge abutment at a speed estimated by
Ugo [173]

Answer:

54.5 kmph

Explanation:

From work-kinetic energy principles, work done by friction on both pavement and gravel shoulder = kinetic energy change of vehicle

ΔK = W = -(f₁d₁ + f₂d₂) where f₁ = frictional force due to pavement = μ₁mg where μ₁ = coefficient of friction of pavement = 0.35, m = mass of vehicle and g = acceleration due to gravity = 9.8 m/s² and d₁ = distance moved by vehicle across pavement = 30 m and

f₂ = frictional force due to gravel shoulder = μ₂mg where μ₂ = coefficient of friction of pavement = 0.50, m = mass of vehicle and g = acceleration due to gravity = 9.8 m/s² and d₂ = distance moved by vehicle across gravel shoulder = 60 m

ΔK = 1/2m(v₁² - v₀²) where v₀ = initial velocity of vehicle, v₁ = final velocity of vehicle = 20 kmph = 20 × 1000/3600 = 5.56 m/s and m = mass of vehicle

So,

ΔK = -(f₁d₁ + f₂d₂)

1/2m(v₁² - v₀²) = -(μ₁mgd₁ + μ₂mgd₂)

1/2(v₁² - v₀²) = -(μ₁gd₁ + μ₂gd₂)

v₁² - v₀² = -2g(μ₁d₁ + μ₂d₂)

v₀² = v₁² + 2g(μ₁d₁ + μ₂d₂)

v₀ = √[v₁² + 2g(μ₁d₁ + μ₂d₂)]

substituting the values of the variables into the equation, we have

v₀ = √[(5.56 m/s)² + 2 × 9.8 m/s²(0.35 × 30 m + 0.5 × 60 m]

v₀ = √[30.91 (m/s)² + 4.9 m/s²(10.5 m + 30 m]

v₀ = √[30.91 (m/s)² + 4.9 m/s²(40.5 m]

v₀ = √[30.91 (m/s)² + 198.45 (m/s)²]

v₀ = √[229.36 (m/s)²

v₀ = 15.14 m/s

v₀ = 15.14 × 3600/1000

v₀ = 54.5 kmph

So, the initial speed of the vehicle is 54.5 kmph

5 0
3 years ago
A violin string has a length of 327mm and produces a note of frequency 440Hz.
Scorpion4ik [409]

The characteristics of the standing wave we can find the backlash for the frequency of the wave when the string is shortened is:

  • The new frequency is f = 657 Hz

<h3>How is a standing wave produced?</h3>

A standing wave is produced when a traveling wave meets an obstacle and bounces, the sum of the two waves results in a wave that does not propagate in space.

In the event that the obstacle is a fixed point, there is a node at this point. The expression for the length of the standing wave.

            L = \frac{\lambda }{2}              fundamental frequency    

            L = 2 \frac{\lambda}{2}            second harmonic          

            L = 3 \frac{\lambda}{2}            third harmonic        

           L = n \frac{\lambda}{2}             general term.

Where L is the length of the chord, lan the wavelength and n an integer.

Wave speed is related to wavelength and frequency.    

       v = λ f.

Let's substitute.          

        v = \frac{2L}{n}  

They indicate that initially the string has a length of L₀ = 327 mm= 0.327m and the frequency is f₀ = 440 Hz.    

          v n = 2L₀ f₀            

          v n = 2 0.327 440            

          v n = 287.76

They indicate that the tension on the string do not changes and the speed of the wave depends only on the tension and the density of the string, therefore it is constant, we assume that the harmonic does not change either, therefore the new length.  

         v n = 2 L f

Let's substitute.          

         287.76 = 2 L f      

         f = \frac{287.76x}{2L}

Let's calculate.      

       f = \frac{287.76}{2 \ 0.219}    

       f = 656.99 Hz

In conclusion with the characteristics of the standing wave we can find the backlash for the frequency of the wave when the string is shortened is:  

  • The new frequency is:  f = 657 Hz

Learn more about standing waves here: brainly.com/question/17031219

6 0
2 years ago
Jaden has a mass of 45 kilograms on Earth. Jupiter has more gravity than the Earth. On Jupiter, Jaden's mass will be O more than
Dovator [93]

Answer:

m = 45 kg

Explanation:

Given that,

Mass of Jadan, m = 45 kg on Earth

Jupiter has more gravity than the Earth.

Mass of an object is the amount of matter contained inside an object. We need to tell about the mass of Jaden on Jupiter. The mass of the object remains same everywhere.It does not change in any of the location.

Hence, Jaden's mass will be 45 kg on Jupiter.

7 0
3 years ago
Sugar is made of carbon, hydrogen, and oxygen atoms. Sugar is
Aneli [31]
D. A solution because it dissolves when mixed with water
7 0
3 years ago
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