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Tomtit [17]
3 years ago
5

Barnard’s Star is a red dwarf. It is located 5.9 light years from Earth. (One light year is the same as 9.46 trillion kilometers

.) This distance in kilometers is how many trillion kilometers is it?
Physics
2 answers:
ValentinkaMS [17]3 years ago
8 0

Answer: 55.814 trillion kilometers

Explanation:       \frac{d}{5.9 light\\years}       \frac{9.46 trillion kilometers}{1 light year}

d (1 light year) = 9.46 trillion kilometers (5.9 light years)

d (1) = 9.46 trillion kilometers (5.9)

d = 55.814 trillion kilometers

mote1985 [20]3 years ago
5 0
A star is located 5.9 light years from Earth.
We know that : 1 light year = 9.46  trillion kilometers.
We will calculate the distance in trillion kilometers multiplying the number of light years by 9.46:
5.9 * 9.46 = 55.814
Answer: The distance is 55.814 trillion km.
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A human hair is approximately 56 µm in diameter.
Ann [662]

Answer:

The diameter is 0.000056 m

Explanation:

Lets explain the relation between the meter and the micrometer

1 Meter is equal to 1000000 (one million) micrometers

1 micrometer = \frac{1}{1000000}=\frac{1}{10^{6}}=10^{-6}

The symbol of the meter is m

The symbol of micrometer is μm

A human hair is approximately 56 µm in diameter

We need to express this diameter in meter

To do that we divide this number by 1,000,000 or multiply it by 10^{-6}

→ \frac{56}{1000000}=0.000056  56 µm = 0.000056 m

→ OR

→ 56*10^{-6}=0.000056

→ 56 µm = 0.000056 m

<em>The diameter is 0.000056 m</em>

4 0
3 years ago
A plane wave with a wavelength of 500 nm is incident normally ona single slit with a width of 5.0 × 10–6 m.Consider waves that r
kaheart [24]

To solve this exercise it is necessary to use the concepts related to Difference in Phase.

The Difference in phase is given by

\Phi = \frac{2\pi \delta}{\lambda}

Where

\delta = Horizontal distance between two points

\lambda = Wavelength

From our values we have,

\lambda = 500nm = 5*10^{-6}m

\theta = 1\°

The horizontal distance between this two points would be given for

\delta = dsin\theta

Therefore using the equation we have

\Phi = \frac{2\pi \delta}{\lambda}

\Phi = \frac{2\pi(dsin\theta)}{\lambda}

\Phi = \frac{2\pi(5*!0^{-6}sin(1))}{500*10^{-9}}

\Phi= 1.096 rad \approx = 1.1 rad

Therefore the correct answer is C.

6 0
3 years ago
How would you calculate an object’s mechanical energy? a. Add its kinetic and potential energies. b. Multiply its kinetic and po
dalvyx [7]
A. Add it's Kinetic and Potential energies
6 0
3 years ago
Read 2 more answers
You are sitting 3 m away from you friend who is watching a cartoon on his phone. How will the sound itensity change if your frie
Zinaida [17]

Answer:

Decreases by $3.6 \times 10^{-3}$ times

Explanation:

The intensity of a sound is defined as the energy of the sound that is flowing in an unit time through the unit area which is in the direction that is perpendicular to the direction of the sound waves movement.

The intensity of energy is described by the inverse square law. It states that the intensity varies inversely with the distance square of the distance.

In other words, the sound intensity decreases as inversely proportional to the squared of the distance.  i.e. $\frac{1}{r^2}$

In the context when the distance was 3 m, the intensity of the sound was = $\frac{1}{9}$

But when the distance became 6 cm or 0.06 m, the sound intensity decreases by =  $\frac{1}{0.06^2}$

                       = $3.6 \times 10^{-3}$ times

3 0
3 years ago
An electromagnetic wave of intensity 150 W/m2 is incident normally on a rectangular black card with sides of 25 cm and 30 cm tha
LenKa [72]

Answer:

3.75 × 10⁻⁸ N

Explanation:

Given:

Intensity of the electromagnetic wave, I = 150 W/m²

Sides of the board = 25 cm (= 0.25 m) and 30 cm (= 0.30 m)

therefore,

the area of the rectangular box, A = 0.25 × 0.30 = 0.075 m²

Now,

force exerted on the card by the radiation, F = \frac{IA}{C}

here,

C is the speed of the light = 3 × 10⁸ m/s

on substituting the respective values, we get

F = \frac{150\times0.075}{3\times10^8}

or

F = 3.75 × 10⁻⁸ N

5 0
3 years ago
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