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Tomtit [17]
3 years ago
5

Barnard’s Star is a red dwarf. It is located 5.9 light years from Earth. (One light year is the same as 9.46 trillion kilometers

.) This distance in kilometers is how many trillion kilometers is it?
Physics
2 answers:
ValentinkaMS [17]3 years ago
8 0

Answer: 55.814 trillion kilometers

Explanation:       \frac{d}{5.9 light\\years}       \frac{9.46 trillion kilometers}{1 light year}

d (1 light year) = 9.46 trillion kilometers (5.9 light years)

d (1) = 9.46 trillion kilometers (5.9)

d = 55.814 trillion kilometers

mote1985 [20]3 years ago
5 0
A star is located 5.9 light years from Earth.
We know that : 1 light year = 9.46  trillion kilometers.
We will calculate the distance in trillion kilometers multiplying the number of light years by 9.46:
5.9 * 9.46 = 55.814
Answer: The distance is 55.814 trillion km.
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Tema [17]

Answer:

Voltage in the primary winding of the coil is 3.9 V

Explanation:

As we know by the principle of transformer we have

\frac{V_s}{V_p} = \frac{N_s}{N_p}

here we know that

V_s = 25 volts

N_s = 3200

N_p = 500

now we have

\frac{25}{V_p} = \frac{3200}{500}

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7 0
3 years ago
The binding energies of K-shell and L-shell electrons in a certain metal are EK and EL, respectively, If a Kαx ray from this met
Svetach [21]

Answer:

The separation distance between the parallel planes of an atom is hc/2sinθ(EK - EL)

Explanation:

The relationship between energy and wavelength is expressed below:

E = hc/λ

λ = hc/EK - EL

Considering the condition of Bragg's law:

2dsinθ = mλ

For the first order Bragg's law of reflection:

2dsinθ = (1)λ

2dsinθ = hc/EK - EL

d = hc/2sinθ(EK - EL)

Where 'd' is the separation distance between the parallel planes of an atom, 'h' is the Planck's constant, 'c' is the velocity of light, θ is the angle of reflection, 'EK' is the energy of the K shell and 'EL' is the energy of the K shell.

Therefore, the separation distance between the parallel planes of an atom is hc/2sinθ(EK - EL)

5 0
3 years ago
A stone is dropped from rest from the top of a cliff into a pond below. If its initial height is 10 m, what is its speed when it
Brut [27]

Answer:

14 m/s

Explanation:

The motion of the stone is a free fall motion, so an accelerated motion with constant acceleration g = 9.8 m/s^2 towards the ground. So, we can use the following SUVAT equation:

v^2 -u^2 = 2gh

where

v is the final speed of the stone as it reaches the water

u = 0 is the initial speed

g = 9.8 m/s^2 is the acceleration

h = 10 m is the distance covered by the stone

Solving for v, we find

v=\sqrt{u^2+2gh}=\sqrt{0+2(9.8 m/s^2)(10 m)}=14 m/s

8 0
3 years ago
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