1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tomtit [17]
3 years ago
5

Barnard’s Star is a red dwarf. It is located 5.9 light years from Earth. (One light year is the same as 9.46 trillion kilometers

.) This distance in kilometers is how many trillion kilometers is it?
Physics
2 answers:
ValentinkaMS [17]3 years ago
8 0

Answer: 55.814 trillion kilometers

Explanation:       \frac{d}{5.9 light\\years}       \frac{9.46 trillion kilometers}{1 light year}

d (1 light year) = 9.46 trillion kilometers (5.9 light years)

d (1) = 9.46 trillion kilometers (5.9)

d = 55.814 trillion kilometers

mote1985 [20]3 years ago
5 0
A star is located 5.9 light years from Earth.
We know that : 1 light year = 9.46  trillion kilometers.
We will calculate the distance in trillion kilometers multiplying the number of light years by 9.46:
5.9 * 9.46 = 55.814
Answer: The distance is 55.814 trillion km.
You might be interested in
When you step inside a warm ski lodge on a cold day, you find your glasses fog. why does this occur?
marin [14]
Answer: Condensation of moisture in the air onto the glasses.

Explanation:
When you come from a cold environment into a warm ski lodge, the glasses are at a much lower temperature than that of the lodge.
Because the air in the room contains moisture (water vapor), it condenses on a surface whose temperature is lower than the dew point of the room. 
5 0
3 years ago
If the only forces acting on a 2.0kg mass are F1 = (3i-8j)N and F2 = (5i+3j)N, what is the magnitude of the acceleration of the
belka [17]

Answer: 4.7m/s²

Explanation:

According to newton's first law,

Force = mass × acceleration

Since we are given more the one force, we will take the resultant of the two vectors.

Mass = 2.0kg

F1+F2 = (3i-8j)+(5i+3j)

Adding component wise, we have;

F1+F2 = 3i+5i-8j+3j

F1+F2 = 8i-5j

Resultant of the sum of the forces will be;

R² = (8i)²+(-5j)²

Since i.i = j.j = 1

R² = 8²+5²

R² = 64+25

R² = 89

R = √89

R = 9.4N

Our resultant force = 9.4N

Substituting in the formula

F = ma

9.4 = 2a

a = 9.4/2

a = 4.7m/s²

Therefore, magnitude of the acceleration of the particle is 4.7m/s²

3 0
3 years ago
Hooke's law describes a certain light spring of unstretched length 33.6 cm. when one end is attached to the top of a doorframe a
masha68 [24]
Missing question: "What is the spring's constant?"

Solution:
The object of mass m=6.89 kg exerts a force on the spring equal to its weight:
F=mg=(6.89 kg)(9.81 m/s^2)=67.6 N
When the object is attached to the spring, the displacement of the spring with respect to its equilibrium position is
\Delta x=43.2 cm-33.6 cm=9.6 cm=0.096 m
And by using Hook's law, we can find the constant of the spring:
k= \frac{F}{\Delta x}= \frac{67.6 N}{0.096 m}=704.2 N/m
4 0
3 years ago
What is it that makes a magnet different from a piece of iron that is not mangetic?​
Alisiya [41]

Answer:

Under normal conditions, a magnetic material like iron doesn't behave like a magnet because the domains don't have a preferred direction of alignment. On the other hand, the domains of a magnet (or a magnetized iron) are all aligned in s specific direction.

7 0
2 years ago
A voltage of 220V (rms) line to netralvoltage is applied across a three phase Y connected resistive load. Each phase of the Y co
mrs_skeptik [129]

Answer:

Current through each phase Vp = 2.2A

Total three phase power Pt= 1.45kW

Power factor of the load pf = 1

Explanation:

i) Find current through each phase

Vp =220V (rms)

Z =100 Ω

I = Vp/Z

 = 220/100

 = 2.2A

ii) Find the total three phase power

for a resistive load, Power, P = VI

Power for each phase is given as:

P = 220 * 2.2

  = 484 W

Total power TP =3* P

                          =484*3

                          = 1452W

                           =1.45kW

 iii) Find the power factor of the load

Phase angle for a resistive load is 0.

α= 0

Hence, power factor of load = cos α

                                          pf      = cos 0

                                             pf    = 1

5 0
3 years ago
Other questions:
  • The law of suggests that the orbit of planets is not circular but .
    8·2 answers
  • -g With what tension must a rope with length 2.50 m and mass 0.120 kg be stretched for transverse waves of frequency 40.0 Hz to
    6·1 answer
  • Describe how we can use scientific knowledge and reasoning to help guide us when making decisions
    12·1 answer
  • The Earth rotates toward the east.<br><br> True False
    13·2 answers
  • While traveling north on an expressway, a car traveling 60 mph (miles per hour) slows down to 30 mph in 12 minutes due to traffi
    10·1 answer
  • Write a paragraph of no less than five sentences explaining how Newton's First Law of Motion supports people's need to wear seat
    12·1 answer
  • BRAINLIEST, PLEASE pls pls pls pls pls pls pls pls pls pls pls plsl plsssssssssssssssssssssssssssssssssssssssssssssssssssssssss
    13·1 answer
  • 39. I also use it when I do the homework. (par 1 line 3).
    15·2 answers
  • Which observation supports a model of the nature of light in which light acts as a wave?
    13·2 answers
  • how to sketch the following?:Sketch ray diagrams for a spherical convex lens with objects at the following distances. (Submit a
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!