Answer:
Initial Kinetic energy of alpha particle is 9.45x10⁻¹³ J .
Explanation:
The distance at which the initial kinetic energy of the particle is equal to the potential energy is known as closest distance. As it is Rutherford scattering, so it is a coulomb potential energy.
Let K be the initial kinetic energy of alpha particle and r be the closest approach distance. So,
Initial Kinetic Energy = Coulomb Potential Energy
K = 
Here, k is constant, e is charge of electron and Z is the atomic number of silver.
Put 9x10⁹ N m²/C² for k, 1.6x10⁻¹⁹ C for e, 47 for Z and 22.9x10⁻¹⁵ m for r in the above equation.
K = 
K = 9.45x10⁻¹³ J
The data set that is most likely from the car equipped with ABS is :
<u><em>Although the plots related to your question is missing attached below is the missing data. </em></u>
The First plot ( acceleration vs time ) plot is the data that represents the application of brakes in a car fitted with ABS ( antilock braking system ) because of the absence of skidding effect between 6.5 and 9 seconds in the graph.
The skidding effect is present in the second plot around the same time because the car is not fitted with ABS
Hence we can conclude that the graph that shows the car fitted with ABS is the first plot .
Learn more : brainly.com/question/4360615
Answer:
In physics, the kinetic energy of an object is the energy that it possesses due to its motion.It is defined as the work needed to accelerate a body of a given mass from rest to its Stated velocity. Having gained this energy during its acceleration, the body maintains the kinetic energy unless it's speed changes.
(or in short)"Energy which a body possesses by virtue of being in motion"
Answer:
Explanation:
Acceleration = a change in velocity / a change in time
Acceleration = ( final velocity - initial velocity) / a change in time
Acceleration = (6m/s - 35 m/s ) / 5 s
= (-29 m/s) /( 5 s)
= - 5.8 m/s^^2
Remember Significant Figures
- 6 m/s^2
P.S I have no idea why the answers say m/s because acceleration is m/s^2.
:)
Answer:

Explanation:
We are given that
Frequency,f=800KHz=

Distance,d=4.5 km=
1 km=1000 m
Electric field,E=0.63V/m
We have to find the magnetic field amplitude of the signal at that point.

We know that


