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lord [1]
2 years ago
11

Would a bottleneck event of the plants in an area from the video at the top of this page result in the need for primary or secon

dary succession?
A: Primary Succession

B: Secondary Succession

subject: Environmental Science
Physics
1 answer:
andriy [413]2 years ago
7 0

The bottleneck event of the plants in an area results in secondary succession.

<h2>What is bottleneck event?</h2>

A bottleneck is an event that drastically reduces the population size of an organism. The bottleneck may be caused by various events, such as an environmental disaster, the hunting or habitat destruction that results in the deaths of organisms.

<h3>Secondary succession</h3>

Secondary succession is a type of ecological succession in which plants and animals recolonize a habitat after a major disturbance such as a devastating flood, wildfire, landslide, lava flow, or human activity e.g., farming or road or building construction.

Learn more about succession here: brainly.com/question/1212975

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HELP is it impossible to experience free fall near the earths surface? why?
kow [346]
It’s not impossible because the gravitational pull from the earths gravity from the atmosphere will pull you in just like all other planets that’s why you can fall at really fast speeds from the air.
3 0
4 years ago
If the coefficient of static friction is 0.40, and the same ladder makes a 51° angle with respect to the horizontal, how far alo
inysia [295]

To solve this problem, we apply the concepts related to the sum of forces and balance in a diagram that will be attached, in order to identify the behavior, direction and sense of the forces. The objective is to find an expression that is in terms of the mass, the angle, the coefficient of friction and the length that allows us to identify when the ladder begins to slip. For equilibrium of the ladder we have,

\sum F_x = 0

\sum F_y = 0

\sum M_o = 0

Now we have that

f_1 = N_2

N_1 = mg

And for equilibrium of the two forces we have finally

mgdcos\theta = N_2lsin\theta

Rearranging to find the distance,

d = \frac{N_2}{mg}ltan\theta

d = \frac{f_1}{mg}ltan\theta

So if we have that the frictional force is equivalent to

f_1 = \mu N_1

f_1 = \mu mg

f_1 = (0.4)(57*9.8)

f_1 = 223.44N

With this value we have that

d = \frac{(0.4)(57)(9.8)}{57*9.8}(7.5) tan(60\°)

d = 5.19m

Therefore can go around to 5.19m before the ladder begins to slip.

5 0
4 years ago
A 1.15-kg mass oscillates according to the equation where x is in meters and in seconds. Determine (a) the amplitude, (b) the fr
ANEK [815]

The complete question is;

A 1.15-kg mass oscillates according to the equation x = 0.650 cos(8.40t) where x is in meters and t in seconds. Determine (a) the amplitude, (b) the frequency, (c) the total energy, and (d) the kinetic energy and potential energy when x = 0.360 m.

Answer:

A) Amplitude; A = 0.650 m

B) Frequency; f = 1.337 Hz

C) total energy = 17.142 J

D) Kinetic energy = 11.884 J

Potential Energy = 5.258 J

Explanation:

We are given;

Mass;m = 1.15 kg

Equation; x = 0.650 cos (8.40t)

(a) The standard form of a wave function is in the form y(x,t) = Asin(kx−ωt+ϕ)

So, comparing terms in our equation in the question to this, the amplitude is;

A = 0.650 m

(b) we know that formula for frequency is;

f = ω/2π

Again, comparing terms in the standard equation and our question, we can see that ω = 8.4

Thus;

f = 8.4/(2π)

f = 1.337 Hz

(c) Formula for the total energy is given by;

E = m•ω²•A²/2

Plugging in the relevant values, we have;

E = (1.15)(8.40)²(0.650)²/2

E = 17.142 J

(d) we want to find the kinetic energy and potential energy when x = 0.360 m.

The formula for kinetic energy in this case is given by;

K = (1/2)•m•ω²•(A² - x²)  

Thus;

K = (1/2) × (1.15) × (8.40)² × ((0.650)² - (0.360)²)

K = 11.884 J

Also, the formula for the potential energy in this case is given by;

U = (1/2)•m•ω²•x²              

Thus;

U = (1/2) × (1.15) × (8.40)² × (0.360)²

U = 5.258 J

3 0
3 years ago
Visible light occupies the majority of the electromagnetic spectrum? Ture or false
Novosadov [1.4K]
From what i can tell its false
5 0
4 years ago
Read 2 more answers
A man holding a rock sits on a sled that is sliding across a frozen lake (negligible friction) with a speed of 0.480 m/s. The to
SpyIntel [72]
This is a problem of conservation of momentum

Momentum before throwing the rock: m*V = 96.0 kg * 0.480 m/s = 46.08 N*s

A) man throws the rock forward

=>

rock:
m1 = 0.310 kg
V1 = 14.5 m/s, in the same direction of the sled with the man

sled and man:
m2 = 96 kg - 0.310 kg = 95.69 kg
v2 = ?

Conservation of momentum:
momentum before throw = momentum after throw

46.08N*s = 0.310kg*14.5m/s + 95.69kg*v2

=> v2 = [46.08 N*s - 0.310*14.5N*s ] / 95.69 kg = 0.434 m/s

B) man throws the rock backward

this changes the sign of the velocity, v2 = -14.5 m/s

 46.08N*s = - 0.310kg*14.5m/s + 95.69kg*v2

v2 = [46.08 N*s + 0.310*14.5 N*s] / 95.69 k = 0.529 m/s


3 0
3 years ago
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