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4 years ago

A stationary front occurs when the boundary surface between two air masses does not _____.

Physics

2 answers:

likoan [24]4 years ago

4 0

When the two air masses meet i think

tatuchka [14]4 years ago

3 0

Answer:

when the two air masses meet.

Explanation:

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A shield of material that reflects neutrons is placed around a radioactive sample. Which change in the nuclear reaction is most

Crazy boy [7]

Answer:

A chain reaction will be sustained in a sub-critical mass.

Explanation:

Hope this helps!

If not, I am sorry.

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2 years ago

Kristina wants to paint the living room a bright blue. Maya prefers the dark blue paint. In other words, they disagree about the

Kruka [31]

Answer:

Intensity

Explanation:

Intensity basically means the amount of light. Hence, they are arguing about the amount of light that one color reflects more than another.

8 0

4 years ago

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What will be the density of the air if the radius of the cylinder is halved while the length is unchanged?

pickupchik [31]

If the radius of the cylinder is halved and length is kept unchanged then the density of air inside the cylinder will increase.

As it can be said that density is inversely proportion to the square of the radius.

Density of Cylinder

Density is the ratio of mass to volume.

The formula for density is: ρ= m/v.

The formula for the Mean Density of a cylinder is:

ρ= m/ (π•r²•h)

where:

ρ is the density of the cylinder

m is the mass of the cylinder

h is the height of the cylinder

So, with increase in radius the of the cylinder there is decrease in the density of cylinder.

And on decreasing the radius of the cylinder there is increase in the density of the cylinder.

As it can be said that density is inversely proportion to the square of the radius.

To learn more about Density Of Cylinder

brainly.com/question/19245086

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8 0

2 years ago

PLEASE SOLVE QUICKLY!!! Solve for A, B, and C from graph

hram777 [196]

A = 59.35cm

B = 196.56g

C = 74.65g

Explanation:

We know,

$x = \frac{L}{\frac{W}{F} +1}$

and L = x+y

Total length, L = 100cm

Weight of Beam, W = 71.8g

Center of mass, x = 49.2cm

Added weight, F = 240g

Position weight placed from fulcrum, y = ?

$L-y = \frac{L}{\frac{W}{F}+1 } \\100 - y = \frac{100}{\frac{71.8}{49.2}+1 } \\100 - y = \frac{100}{1.46+1}\\\\100 - y = \frac{100}{2.46} \\100-y = 40.65\\\\y = 59.35cm$

Therefore, position weight placed from fulcrum is 59.35cm

Total length, L = 100cm

Center of mass, x = 47.8 cm

Added weight, F = 180g

Position weight placed from fulcrum, y = 12.4cm

Weight of Beam, W = ?

$47.8 = \frac{100}{\frac{W}{180}+1 }\\\47.8 = \frac{100}{\frac{W+180}{180} } \\\\47.8 = \frac{100 X 180}{W+180}\\ \\47.8W + 47.8 X 180 = 18000\\47.8W = 18000 - 8604\\W = \frac{9396}{47.8}\\ W = 196.56g$

Therefore, weight of the beam is 196.56g

Total length, L = 100cm

Center of mass, x = 50.8 cm

Position weight placed from fulcrum, y = 9.8cm

Weight of Beam, W = 72.3g

Added weight, F = ?

$50.8 = \frac{100}{\frac{72.3}{F}+1 }\\\ 50.8 = \frac{100}{\frac{72.3+F}{F} } \\\\50.8 = \frac{100 X F}{72.3+F}\\ \\50.8 X 72.3 + 50.8 X F = 100F\\\\3672.84 = 100F-50.8F\\3672.84 = 49.2F\\F = 74.65g$

Therefore, Added weight F is 74.65g

A = 59.35cm

B = 196.56g

C = 74.65g

4 0

3 years ago

Hey if you talk to me i will mark you as a brainliest and if you answer all my question

Fittoniya [83]

Answer:

what will happen if i will answer ur questions?

Explanation:

is there gonna be a bad thing or a good thing

5 0

3 years ago

Read 2 more answers