<em>An is formed when an atom loses or gains one or more electrons. Because the number of electrons in an ion is different from the number of protons, an ion does have an overall electric charge. Consider how a positive ion can form from an atom. The left side of the illustration below represents a sodium (Na) atom</em>
Answer:
C. 3m/s
Explanation:
Since we ignore air resistant, horizontally speaking, theres no force acting on the ball. According to Newton's 1st law of motion, when there's no force, the object will stays in the same velocity.
In this case after, the ball velocity would still be 3m/s
Answer:
8.6 m/s
Explanation:
The observer is stationary
The source is moving
Let v₀ be the speed of sound in the air
Let v be the speed of the ambulance
As the siren approaches
f₁ = 2000(v₀ / (v₀ - v))
As the siren departs
f₁' = 2000(v₀ / (v₀ + v))
f₁ - f₁' = 100
2000(v₀ / (v₀ - v)) - 2000(v₀ / (v₀ + v)) = 100
v₀ / (v₀ - v) - v₀ / (v₀ + v) = 100/2000
v₀(v₀ + v) / (v₀ - v)(v₀ + v) - v₀(v₀ - v) / (v₀ - v)(v₀ + v) = 0.05
(v₀² + vv₀) - (v₀² - vv₀) / (v₀² - v²) = 0.05
2vv₀ / (v₀² - v²) = 0.05
2vv₀ = 0.05 (v₀² - v²)
0.05v² + 2vv₀ - 0.05v₀² = 0
v² + 40vv₀ - v₀² = 0
quadratic formula positive answer
v = (-40v₀ + √((40v₀)² - 4(1)(v₀²))) / 2
v = (-40v₀ + √(1604v₀²)) / 2
v = (0.049968v₀) / 2
v = 0.02498439v₀
If we assume the speed of sound in air is 343 m/s
v = 8.56964... = 8.6 m/s
Approaching frequency heard is 2051 Hz
Departing frequency heard is 1951 Hz
Answer:
3.77 Hz
Explanation:
The beat frequency that is heard can be calculated using the following equation:
<u>Where:</u>
f₁ = 110 Hz
<u>With:</u>
<em>T₁ = 594 N </em>
<em>T₂ = 554 N </em>
Hence, the beat frequency is:
Therefore, the beat frequency that is heard when the hammer strikes the two strings simultaneously is 3.77 Hz.
I hope it helps you!
Answer:
17.5 N
Explanation:
<h2>Given :</h2>
- Mass (m) = 2.5 kg
- Acceleration (a) = 7.0 m/s²
<h2>To calculate :</h2>
<h2>Calculation :</h2>
<h3>• F = ma</h3>
→ F = (2.5 × 7.0) N
→ F = 25/10 × 7 N
→ F = 5/2 × 7 N
→ F = (5 × 7)/2 N
→ F = 35/2 N
→ <u>F</u><u> </u><u>=</u><u> </u><u>1</u><u>7</u><u>.</u><u>5</u><u> </u><u>N</u><u> </u><u>towards</u><u> </u><u>left</u>
Hence, 17.5 N of net force must act on the book to make it accelerate to the left.