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ANEK [815]
4 years ago
15

Alisha uses wire to connect a battery, a lightbulb, and a switch, but the bulb does not light up even though the switch is in th

e closed position. Which might explain the problem?
Physics
1 answer:
mojhsa [17]4 years ago
5 0

Alisha uses wire to connect a battery, a lightbulb, and a switch, but the bulb does not light up even though the switch is in the closed position. The switch is in closed position that is why her circuit would not work. It must be open so that electrons can move along the wire and enable the lightbulb to light up.

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If an electric wire is allowed to produce a magnetic field no larger than that of the Earth (0.503 X 104 T) at a distance of 15
dem82 [27]

Answer:

37.725 A

Explanation:

B = magnitude of the magnetic field produced by the electric wire = 0.503 x 10⁻⁴ T

r = distance from the wire where the magnetic field is noted = 15 cm = 0.15 m

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Magnetic field by a long wire is given as

B = \frac{\mu _{o}}{4\pi }\frac{2i}{r}

Inserting the values

0.503\times 10^{-4} = (10^{-7})\frac{2i}{0.15}

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You slide a slab of dielectric between the plates of a parallel-plate capacitor. As you do this, the potential difference betwee
LUCKY_DIMON [66]

Answer:

In this scenario adding the dielectric material in between the plates will have no effect on the capacitance of the plates since the voltage remains unchanged

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Voltage and capacitance are inversely proportional when charge is constant.

Now in this case the voltage remains the same hence the charges remain the same also because voltage is inversely proportional to capacitance

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