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ANEK [815]
3 years ago
15

Alisha uses wire to connect a battery, a lightbulb, and a switch, but the bulb does not light up even though the switch is in th

e closed position. Which might explain the problem?
Physics
1 answer:
mojhsa [17]3 years ago
5 0

Alisha uses wire to connect a battery, a lightbulb, and a switch, but the bulb does not light up even though the switch is in the closed position. The switch is in closed position that is why her circuit would not work. It must be open so that electrons can move along the wire and enable the lightbulb to light up.

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A mango falls fromthe top its tree passing a window which is 2.4m tall by taking 0.4s
Natasha2012 [34]

Explanation:

There are three points in time we need to consider.  At point 0, the mango begins to fall from the tree.  At point 1, the mango reaches the top of the window.  At point 2, the mango reaches the bottom of the window.

We are given the following information:

y₁ = 3 m

y₂ = 3 m − 2.4 m = 0.6 m

t₂ − t₁ = 0.4 s

a = -9.8 m/s²

t₀ = 0 s

v₀ = 0 m/s

We need to find y₀.

Use a constant acceleration equation:

y = y₀ + v₀ t + ½ at²

Evaluated at point 1:

3 = y₀ + (0) t₁ + ½ (-9.8) t₁²

3 = y₀ − 4.9 t₁²

Evaluated at point 2:

0.6 = y₀ + (0) t₂ + ½ (-9.8) t₂²

0.6 = y₀ − 4.9 t₂²

Solve for y₀ in the first equation and substitute into the second:

y₀ = 3 + 4.9 t₁²

0.6 = (3 + 4.9 t₁²) − 4.9 t₂²

0 = 2.4 + 4.9 (t₁² − t₂²)

We know t₂ = t₁ + 0.4:

0 = 2.4 + 4.9 (t₁² − (t₁ + 0.4)²)

0 = 2.4 + 4.9 (t₁² − (t₁² + 0.8 t₁ + 0.16))

0 = 2.4 + 4.9 (t₁² − t₁² − 0.8 t₁ − 0.16)

0 = 2.4 + 4.9 (-0.8 t₁ − 0.16)

0 = 2.4 − 3.92 t₁ − 0.784

0 = 1.616 − 3.92 t₁

t₁ = 0.412

Now we can plug this into the original equation and find y₀:

3 = y₀ − 4.9 t₁²

3 = y₀ − 4.9 (0.412)²

3 = y₀ − 0.83

y₀ = 3.83

Rounded to two significant figures, the height of the tree is 3.8 meters.

6 0
2 years ago
In the table below,which statement would best fill the missing box under isolated systems?
Nostrana [21]

Answer:

b-energy is not exchanged

Explanation:

An isolated system is a thermodynamic system in which neither energy nor matter is exchanged with the surroundings.

As such the best statement that will fill the box under an isolated system is that energy is not exchanged.

  • In an open system, both matter and energy are exchanged with the surrounding.
  • A closed system is one in which energy transfer is permissible but matter is not exchanged.
  • Energy cannot be created nor destroyed in any system. They are simply transformed.
3 0
3 years ago
A 0.5 kg yellow bouncy ball rolls to the right at a speed of 8 m/s while a 0.25 kg blue bouncy ball rolls
inessss [21]

Explanation:

Let yellow ball be m1 = 0.5kg with u1 = 8 m/s and blue ball be m2 = 0.25 kg with u2 = - 4 m /s respectively.

After collision, blue ball travels 12 m/s.

<u>Using conservation of Linear Momentum</u> :

m1u1 + m2u2 = m1v1 + m2v2

0.5* 8 + 0.25 * - 4 = 0.5 * v1 + 0.25 * 12

v1 = 0 m/sec i.e. <u>Yellow ball comes to rest</u>.

3 0
2 years ago
How much work is the adult completing<br> 1.6j<br> 0.6j<br> 20j<br> 1,500j<br> I NEED THIS DONE FAST
koban [17]

Answer:

20j

Explanation:

espero haverte

ayudado

6 0
2 years ago
Suppose you have a toy car made of copper. The car has the mass of 224 grams. What is the volume of your toy car?
melamori03 [73]

Answer:

Volume = 25 cm^3

Explanation:

We know that the density of any kind of substance or material is equal to:

density= mass/volume\\\\densitycopper= 8.96gram/cm^3\\mass=224grams\\volume=mass/density\\\\volume=224/8.96 = 25 cm^3

3 0
2 years ago
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