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Dafna1 [17]
4 years ago
8

When a cell is in a solution where the concentration of solute is the same in the cell as in the solution, the solution is calle

d?
Chemistry
1 answer:
Elodia [21]4 years ago
7 0
The answer to this question would be: isotonic

An isotonic solution has a same tonicity/concentration to the cell. This kind of solution will not cause osmosis to occur so it wouldn't shrink or swell the cells. This is why an isotonic solution is safer for the cells. The normal saline solution is isotonic to human cells and used frequently in medicine to replace body fluid.
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To determine the molarity of NaOH solution, student took 3.5 g of KHP (KHP – Potassium hydrogen phthalate; Molar mass = 204.22 g
nika2105 [10]
KHP molarity = (3.5/204.22) x (1000/50) = 0.343 M
NaOH volume = 24.65 - 1.85 = 22.8 ml
Molarity of NaOH = (weight/40) x (1000/22.8) = 1.096W
                                KH₂PO₄ + NaOH → NaKHPO₄ + H₂O
initial                         0.343       1.096W       0                 0
after reaction (0.343 - 1.096W)     0         1.096W        1.096W
KH₂PO₄ and NaKHPO₄ is considered as buffer and its (H₂PO₄⁻) pKa value is 7.21
phenolphthalein indicator turns pink means it is at the equivalence point
so pH = pKa
by using buffer equation
pH = pKa + log [salt] / [acid]
when pH = pKa so [salt] = [acid]
1.096 W = 0.343 - 1.096W
2.192 W = 0.343
W = 0.156 g
NaOH molarity = 1.096 W = 1.096 x 0.156 = 0.17 M
Molarity of NaOH = 0.17 M
8 0
3 years ago
What is the importance of dissolved co2 and o2 in water
hodyreva [135]

Answer:

The oxygen O2, and the carbon dioxide (CO2) dissolved in water are very important to keep live in aquatic bodies.

Explanation:

Oxygen (O2) is an element found in nature usually as a gas in the air that we breathe. Oxygen is very important for aerobic organisms, including us, the humans. It can dissolve in water, and it is vital for the health of aquatic habitats. If we have low quantity of oxygen dissolve in water means that could be a pollution problem. Actually the oxygen level is an indicator to determine the water quality. In order to survive the aquatic biota (animals and plants) need certain quantity of oxygen. The oxygen dissolved in the water comes from the air, because of the wind, rain, waves, currents, and from aquatic plants like algae thanks to a process call photosynthesis.

Carbon Dioxide (CO2) is a chemical compound. This gas also is found in the air, and can be dissolved in water easier than oxygen. Aquatic plants needs CO2, to produce their own food during the photosynthesis process. It´s very important to have enough CO2, for the growth of aquatic plants. But if we have to much CO2 the fish will not have enough oxygen and could suffocate and die. Aquatic animals through respiration process produce CO2, it also can be obtained from fermentation, and from the burning of any substance that has carbon C.

If we want to preserve live in the aquatic bodies we must keep the balance between oxygen and carbon dioxide.

4 0
3 years ago
What number of cations is present in 1.17g of sodium chloride ?
taurus [48]

Answer:

1.2 × 10^22 atoms.

Explanation:

Firstly, cations refers to the positively charged atom in the ionic compound, which is Na+.

Given the mass of NaCl as 1.17g, the number of moles of NaCl can be calculated this:

Molar mass of NaCl = 23 + 35.5

= 58.5g/mol

Mole = mass/molar mass

Mole = 1.17/58.5

Mole = 0.02moles

Using Avagadro's number, 6.022 × 10^23 atoms of Na+ are in 1 mole of NaCl.

In 0.02 moles of NaCl, there are 0.02 × 6.022 × 10^23 of Na+

0.1204 × 10^23 atoms

1.2 × 10^22 atoms of Na+ (cation)

5 0
3 years ago
The molecule
lorasvet [3.4K]

Answer:cellulose

Explanation:

I just did it.

8 0
3 years ago
Under certain conditions, the substance calcium carbonate can be broken down to form calcium oxide and carbon dioxide. If 31.7 g
klio [65]

Answer:

13.93\ \text{g}

Explanation:

Molecular weight of CaCO_3 = 100.0869 g/mol

Mass of CaCO_3 = 31.7 g

Moles of CaCO_3 = \dfrac{31.7}{100.0869}=0.3167\ \text{mol}

Moles of both CaO and CO_2 is 0.3167\ \text{mol}

Molecular weight of CO_2 = 44 g/mol

Mass of CO_2 = 44\times 0.3167=13.93\ \text{g}

The mass of carbon dioxide formed simultaneously is 13.93\ \text{g}.

6 0
3 years ago
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