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Lorico [155]
3 years ago
11

Why are scientific models important in the study of science?

Chemistry
1 answer:
telo118 [61]3 years ago
7 0

Answer:

In science, amodel is a representation of an idea, an object or even a process or a system that is used to describe and explain phenomena that cannot be experienced directly. Models are central to what scientists do, both in their research as well as when communicating their explanations.

Explanation:

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In order to determine if 2 atoms are cooper what must be the same for each
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-number of electrons
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3 years ago
A base has Kb of 2.5 x 10-11. which of the following statements is true?(1 point)
Furkat [3]
I disagree with the answer pick of D. If you have a neutral pH 7 solution and you proceed to add a base even with an relatively insignificantly low Kb your solution would still be more basic then acidic. The answer should be b which is true that the base only ionizes slightly in aqueous solution. This is also truer to the definition of what Kb represents.
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A box is 1 m high, 2.5 m long, and 1.5 m wide, its volume is 5 mº.<br> true or false
Maurinko [17]

Answer:

false

Explanation:

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5 0
2 years ago
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CAN SOMEONE REWRITE/SHORTEN THIS FOR ME PLEASE? I'LL GIVE BRAINLIEST
Alex17521 [72]

Answer:

Here you go! 50% of your writing piece

Explanation:

Foods produced from or using GM organisms are often referred to as GM foods.

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7 0
3 years ago
For many purposes we can treat ammonia NH3 as an ideal gas at temperatures above its boiling point of −33.°C. Suppose the temper
Keith_Richards [23]

Answer:

The new pressure will be 0.225 kPa.

Explanation:

Applying combined gas law:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1\text{ and }V_1 are initial pressure and volume at initial temperature T_1.

P_2\text{ and }V_2 are final pressure and volume at initial temperature T_2.

We are given:

P_1=0.29 kPa\\V_1=V\\P_2=?\\V_2=V+50\% of V=1.5 V

T_1=-25^oC=248.15 K

T _2 = 16^oC=289.15 K

Putting values in above equation, we get:

\frac{0.29 kPa\times V}{248.15 K}=\frac{P_2\times 1.5V}{289.15 K}

P_1=0.225 kPa

Hence, the new pressure will be 0.225  kPa.

4 0
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