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Naya [18.7K]
3 years ago
14

Which of the following ways is usable energy lost?

Physics
2 answers:
Vsevolod [243]3 years ago
5 0
The answer to your question is D all of the above
tamaranim1 [39]3 years ago
4 0
A. Friction or all of the above
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A charge Q acts on a point charge to create an electric field. Its strength, measured a distance of 40 cm away is 100 N/C. What
KIM [24]

Answer:

E_2=80N/C

Explanation:

From the question we are told that:

Initial Distance d_1=40cm=>0.4m

Initial Electric field strength E_1=100N/C

Final Distance d_2=20cm=>0.20m

Generally the equation for Electric field is mathematically given by.

 E=\frac{kq}{d^2}

 q=\frac{100*(0.4)^2}{K}

Substituting q for d=20cm

 E_2=\frac{k}{0.2}*\frac{100*(0.4)^2}{K}

 E_2=80N/C

6 0
3 years ago
I need help with answer 51.
Troyanec [42]

Answer:

2

Explanation:

5 0
2 years ago
IF THERE ARE ONLY 118 ELEMENTS, HOW DO YOU
expeople1 [14]

Answer:

Although there are only 118 elements that have been discovered and entered in the Periodic Table, there is an almost infinite multiplicity of things, materials, resources and other objects in the universe.

This is so because each of these elements can be combined with the others, varying its proportion and the inclusion of different elements, forming different things according to the proportion in which each element has been used.

7 0
3 years ago
A potter's wheel has the shape of a solid uniform disk of mass 13.0 kg and radius 1.25 m. It spins about an axis perpendicular t
Fittoniya [83]

Answer:10.82 kg-m^2

Explanation:

Given

Mass of solid uniform disk M=13 kg

radius of disk r=1.25 m

mass of lump m=1.7 kg

distance of lump from axis r_0=0.63

Moment of inertia is the distribution of mass from the axis of rotation

Initial moment of inertia of disk I_1=\frac{Mr^2}{2}

I_1=\frac{13\times 1.25^2}{2}=10.15 kg-m^2

Final moment of inertia I_f=Moment of inertia of disk+moment of inertia of lump about axis

I_f=\frac{Mr^2}{2}+mr_0^2

I_f=10.15+1.7\times 0.63^2

I_f=10.15+0.674

I_f=10.82 kg-m^2

3 0
4 years ago
A person jumps out a fourth-story window 14 m above a firefighter safety net. The survivor stretches the net 1.8 m before coming
Monica [59]

Answer:

The deceleration is  a =  - 76.27 m/s^2

Explanation:

From the question we are told that

   The height above  firefighter safety net is H  = 14 \ m

   The length by which the net is stretched is s =  1.8 \ m

   

From the law of energy conservation

    KE_T + PE_T =  KE_B + PE_B

 Where KE_T is the kinetic energy of the person before jumping which equal to zero(because to kinetic energy at maximum height )

   and  PE_T is the potential energy of the before jumping  which is mathematically represented at

          PE_T  = mg H

and  KE_B is the kinetic energy of the person just before landing on the safety net  which is mathematically represented at

        KE_B = \frac{1}{2} m v^2

and  PE_B is the potential energy of the person as he lands on the safety net which has a value of zero (because it is converted to kinetic energy )

   So the above equation becomes

          mgH =  \frac{1}{2} m v^2

=>           v =  \sqrt{2 gH }

    substituting values

                v =  16.57 m/s

Applying the equation o motion

             v_f =  v  + 2 a s

Now the final velocity is zero because the person comes to rest

      So

         0 = 16.57 + 2 * a * 1.8

            a =  - \frac{16.57^2 }{2 * 1.8}

            a =  - 76.27 m/s^2

         

         

4 0
3 years ago
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