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sergeinik [125]
3 years ago
8

A 4kg mass traveling eastwards at 4m.s per second collides with a 3kg mass traveling westward as 8m.s per second..calculate the

total momentum of mass before they colide
Physics
1 answer:
quester [9]3 years ago
7 0
The following instructions are my idea.

P=m*v

1. notice that the to masses move in opposite directions -> one has positive and one has negative speed

2. P1=4*(-4)=-16[kg*m/s]
P2=3*8=24[kg*m/s]
3. Add the momentums:

P1+P2=-16+24=8[kg*m/s]

The total momentum of mass equals 8 kg*m/s
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I need help getting started with number 8.
ratelena [41]

In #8, the distance and the (magnitude of displacement) are equal, because he crawled in a straight line.

Displacement = (straight-line distance from start-point to end-point) in the direction from start to end, regardless of what route was actually followed.

Displacement = 5m, in the negative direction.

In #9 . . . distance will be the same.  Displacement is going to be the same magnitude, but in the positive direction.

This is so simple that it's hard to talk about.  

In #8, "What was the bug's distance ?". "Distance was 5 meters.".  "What was the bug's displacement ?", "Displacement was 5 meters backwards."

In #9, What was the bug's distance ?". "Distance was 5 meters.".  "What was the bug's displacement ?", "Displacement was 5 meters forward."

4 0
2 years ago
Positive electric charges are always attracted to ________ charges.
Georgia [21]

Answer:

Negative electric charges

4 0
2 years ago
A 2.4-m high 200-m2 house is maintained at 22°C by an air-conditioning system whose COP, is 3.2. It is estimated that the kitch
kotegsom [21]

Answer:

The amount that is "vented" out by "the fans" is <u>$0.50</u> for 10 hours.

Option: a

<u>Explanation</u>:

"Energy discharged by air in every hour" can be determined by,

\mathrm{Q}=\mathrm{m}_{\mathrm{air}} \mathrm{C}_{\mathrm{p}} \Delta \mathrm{T}

Q = heat energy (Joules, J)  

m = mass of a substance (kg)  

c = specific heat (units J/kg∙K)  

\mathrm{m}_{\mathrm{air}}=\rho \mathrm{v}

\text { Density of air } \rho=1.20 \mathrm{kg} / \mathrm{m}^{3}

\text { Density of air } \rho=1.20 \times 200 \times 2.4

\text { Density of air } \rho=576 \mathrm{kg}

∆T = 10 hours

\text { Specific Heat Capacities of Air. The nominal values used for air at } 300 \mathrm{K} \text { are } \mathrm{C_P}=1.00 \mathrm{kJ} / \mathrm{kg} . \mathrm{K}

Q = 576 × 1.00 × 10

Q = 5760 kJ/hours

W = 1.6 kwh

We know that, “Coefficient of performance” (COP)

\mathrm{Cop}=\frac{Q}{w}

\mathrm{W}=\frac{Q}{\mathrm{cop}}

Given that, COP = 3.2

\mathrm{W}=\frac{1.6}{3.2}

W = 0.5 kwh

The unit cost of electricity is $0.10/kWh

The unit cost of electricity is $0.10/kWh

Unit electricity cost for 10 hours = 0.5 × 10 × 0.1$

Unit electricity cost for 10 hours = $0.5

The amount that is "vented out" by "the fans" is $0.50 for 10 hours.

6 0
3 years ago
Grace pushes her foot against the wall with a force of 35 N while she stands
Airida [17]

Answer:

The correct answer is B. 0.64 m/s²

Explanation:

According to the Newton's Second law of motion acceleration of an object by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force.

Mathematically,

                           F ∝ a

                           F = ma

Given data:

Force = F = 35 N

Mass = m = 55 kg

acceleration = a = ?

                           F = ma

                           a = F/m

                           a = 35/55

                          a = 0.64 m/s²

5 0
3 years ago
What happens when an electron absorbs a photon
nordsb [41]

Explanation:

A small piece of energy is called as Electron. It cannot be broken down further into smaller pieces. Photon is a basic unit of light. Photons always travel. They are in a continuous motion. So when electron needs energy, They absorb light. The light is absorbed or emitted in the form of photons. Each photon contains energy which is absorbed by the electron to gain its energy. After absorbing the photon, electron moves towards a higher energy level. So when an electron absorbs a photon, energy is gained by the electron.

7 0
3 years ago
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