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LuckyWell [14K]
2 years ago
10

PLEASE HELP!!!

Physics
1 answer:
anzhelika [568]2 years ago
7 0

The net force that is applied to the passenger during the elevator acceleration is 218.75 N.

<h3>What is net force?</h3>

This is the single force obtained from the combinatiion of two or more forces

To calculate the net force that is applied to the passenger during the elevator's acceleration, we use the formula below.

Formula:

  • F = m(v-u)/t............ Equation 1

Where:

  • F = force
  • m = mass
  • v = Final velocity
  • u = initial velocity
  • t = time.

From the question,

Given:

  • m = 70 kg
  • u = 0 m/s
  • v = 12.5 m/s
  • t = 4 s

Substitute these values into equation 1

  • F = 70(12.5-0)/4
  • F = 218.75 N

Hence, The net force that is applied to the passenger during the elevator acceleration is 218.75 N.

Learn more about net force here: brainly.com/question/13370981

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<u>Answer:</u> The Young's modulus for the wire is 6.378\times 10^{10}N/m^2

<u>Explanation:</u>

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The equation representing Young's Modulus is:

Y=\frac{F/A}{\Delta l/l}=\frac{Fl}{A\Delta l}

where,

Y = Young's Modulus

F = force exerted by the weight  = m\times g

m = mass of the ball = 10 kg

g = acceleration due to gravity = 9.81m/s^2

l = length of wire  = 2.6 m

A = area of cross section  = \pi r^2

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\Delta l = change in length  = 1.99 mm = 1.99\times 10^{-3}m

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