There is no displacement. The frog is back where it began.
Answer: work
Explanation:
Often in physics, work is defined as the use of force to move an object. Technically, work is actually a change in energy caused by a force external to the system. The formula for work is W = F⊥d or W = FdcosΘ. Using this formula, we can see that work is just when a force is applied for a certain displacement. In simpler terms, that's just a force used to move an object a certain distance.
The magnitude of the force is 18.6 N
Explanation:
The work done by a force on an object is given by
where
F is the magnitude of the force
d is the displacement of the object
is the angle between the direction of the force and of the displacement
For the block in this problem, we have
is the work done
d = 1.35 m is the displacement of the block
is the angle between the force and the displacement
Solving for F, we find the magnitude of the force:
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Answer:
0m/s²
Explanation:
The acceleration of the given body whose motion has been described will be zero.
This is because the body moves with a constant velocity.
Acceleration is defined as the rate of change of velocity with time.
Since in this problem, the velocity is not changing per time, then the acceleration would be zero.
A body moving steadily implies that such body is not changing its motion by the virtue of its velocity and even direction.
Answer:
<em>The difference in pressure between the external air pressure, and the internal air pressure of the middle ear.</em>
Explanation:
First of all, we should note that pressure decreases with height and increases with depth. The air within the middle ear (between the ear drum and the Eustachian tube) adjusts itself to respond to the atmospheric pressure, or when we yawn. At a high altitude like on the hill, the air pressure in the middle ear, is fairly low (this is to balance the low air pressure at this height). While riding down the hill quickly, there is little time for the air pressure in the ear to readjust itself to the increasing external air pressure, causing the external air to push into the ear drum. Along the way, the air within the middle ear is adjusted by the opening of the Eustachian tube, allowing more air into the space in the middle ear to balance the external air pressure. This readjustment causes the ear to pop.
