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3 years ago

24 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Chemistry

2 answers:

telo118 [61]3 years ago

7 0

Its B because it goes straight up

stellarik [79]3 years ago

6 0

<u>Answer:</u> The correct answer is Graph B.

<u>Explanation:</u>

Inertia is the property of a matter due to its mass. Due to inertia, a body resits any change in its state of rest or motion. Newton's first law is based on inertia and is also known as Law of inertia.

This law states that any body will remain at rest or in motion until and unless an external force is applied on it.

Inertia is directly related to the mass of a substance. As, the mass is more, its inertia will be more and vice-versa.

The graph will represents the direct relation is Graph B. As, the mass is increasing, the inertia is also increasing

Hence, the correct answer is Graph B.

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k0ka [10]

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4 years ago

Read 2 more answers

Choose the best answer below. Which of the following reactions will have the largest equilibrium constant at 298 K?

Maurinko [17]

Answer:

Explanation:

Relation between ΔG₀ and K ( equilibrium constant ) is as follows .

lnK = - ΔG₀ / RT

$K = e^{-\frac{\triangle G_0}{RT}$

The value of R and T are same for all reactions .

So higher the value of negative ΔG₀ , higher will be the value of K .

Mg(s) + N₂0(g) → MgO(s) + N₂(g)

has the ΔG₀ value of -673 kJ which is highest negative value . So this reaction will have highest value of equilibrium constant K .

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3 years ago

Please complete the sentence. You can separate the parts of any mixture by using _____________ processes.

elena55 [62]

I believe the answer is filtration.

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4 years ago

Read 2 more answers

Some SbCl5 is allowed to dissociate into SbCl3 and Cl2 at 521 K. At equilibrium, [SbCl5] = 0.195 M, and [SbCl3] = [Cl2] = 6.98×1

Brilliant_brown [7]

Answer:

a) The equilibrium will shift in the right direction.

b) The new equilibrium concentrations after reestablishment of the equilibrium :

$[SbCl_5]=(0.370-x) M=(0.370-0.0233) M=0.3467 M$

$[SbCl_3]=(6.98\times 10^{-2}+x) M=(6.98\times 10^{-2}+0.0233) M=0.0931 M$

$[Cl_2]=(6.98\times 10^{-2}+x) M=(6.98\times 10^{-2}+0.0233) M=0.0931 M$

Explanation:

$SbCl_5(g)\rightleftharpoons SbCl_3(g) + Cl_2(g)$

a) Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

On increase in amount of reactant

$SbCl_5(g)\rightleftharpoons SbCl_3(g) + Cl_2(g)$

If the reactant is increased, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where more product formation is taking place. As the number of moles of $SbCl_5$ is increasing .So, the equilibrium will shift in the right direction.