Answer: False
Explanation:
4C2H6 + 7O2 --> 6H2O + 4CO2
8 Carbons on the reactant side, but 4 Carbons on the Product
24 Hydrogens on Reactant, 12 H on product
But Oxygen is balanced, 14 on each side
Answer:
Q = 30284.88 j
Explanation:
Given data:
Mass of ethanol = 257 g
Cp = 2.4 j/g.°C
Chnage in temperature = ΔT = 49.1°C
Heat required = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Now we will put the values in formula.
Q = 257 g× 2.4 j/g.°C × 49.1 °C
Q = 30284.88 j
Answer:
The molarity of the solution increases.
Explanation:
Molarity is the measure of the concentration of the solute in the solution. In this case, the solvent is the sugar solution and the solute is the sugar.
If sugar is ADDED to the already sugary solution, then there would be more sugar. Therefore, the sugar (solute) would increase in number.
This means that the answer is the third choice: The molarity of the solution increases.
The answer would not be the first or second choice because there isn't anything in the question that implies water. It just says sugar solution.
The answer is not the last choice because the sugar concentration does not decrease after you have added more sugar to it. It increases.
Answer: A. The oceans‘ tidal would be smaller because the moon would exert less gravitational pull on earths oceans.
Explanation:
i got it right :)
Molarity is defined as the ratio of number of moles to the volume of solution in litres.
The mathematical expression is given as:

Here, molarity is equal to 1.43 M and volume is equal to 785 mL.
Convert mL into L
As, 1 mL = 0.001 L
Thus, volume =
= 0.785 L
Rearrange the formula of molarity in terms of number of moles:

n = 
= 1.12255 mole
Now, Number of moles = 
Molar mass of potassium hydroxide = 56.10 g/mol
1.12255 mole = 
mass in g =
= 62.97 g
Hence, mass of
= 62.97 g