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3 years ago

Mengapa dinding kapilari darah berbeza berbanding dinding vena dan arteri

Chemistry

1 answer:

olga55 [171]3 years ago

5 0

Answer:

Kapilari lebih kecil dan paling banyak saluran darah, mereka membentuk sambungan antara vesel yang membawa darah dari pendengaran (arteri) dan vesel yang mengembalikan darah ke jantung (urat)

Fungsi utama kapilari ialah pertukaran bahan antara sel darah dan tisu.

Veins membawa darah ke arah jantung; selepas ia melewati kapilari dan masuk melalui urat terkecil (venules).

Arteri membawa darah dari jantung; arteri sistemik mengangkut darah oksigen dari ventrikel kiri ke tisu badan.

Explanation:

(translated version)

Why blood capillary walls differ from veins and arteries

Capillaries are smaller and the most numerous of the blood vessels, they form the connection between the vessels that carry blood away from the hear (arteries) and the vessels that return the blood to the heart (veins)

The primary function of the capillaries is the exchange of materials between the blood and tissue cells.

Veins carries the blood towards the heart; after it passes through the capillaries and enters through the smallest veins (venules).

Arteries carries blood away from the heart; systemic arteries transport oxygenated blood from the left ventricle to the body tissues.

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3 years ago

A solution was prepared by dissolving 195.0 g of KCl in 215 g of water. Calculate the mole fraction of KCl. (The formula weight

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Answer:

Approximately $0.180$ .

Explanation:

The mole fraction of a compound in a solution is:

$\displaystyle \frac{\text{Number of moles of compound in question}}{\text{Number of moles of all particles in the solution}}$ .

In this question, the mole fraction of $\rm KCl$ in this solution would be:

$\displaystyle X_\mathrm{KCl} = \frac{n(\mathrm{KCl})}{n(\text{All particles in this soluton})}$ .

This solution consist of only $\rm KCl$ and water (i.e., $\rm H_2O$ .) Hence:

$\begin{aligned} X_\mathrm{KCl} &= \frac{n(\mathrm{KCl})}{n(\text{All particles in this soluton})}\\ &= \frac{n(\mathrm{KCl})}{n(\mathrm{KCl}) + n(\mathrm{H_2O})}\end{aligned}$ .

From the question:

Mass of $\rm KCl$ : $m(\mathrm{KCl}) = 195.0\; \rm g$ .
Molar mass of $\rm KCl$ : $M(\mathrm{KCl}) = 74.6\; \rm g \cdot mol^{-1}$ .

Mass of $\rm H_2O$ : $m(\mathrm{H_2O}) = 215\; \rm g$ .
Molar mass of $\rm H_2O$ : $M(\mathrm{H_2O}) = 18.0\; \rm g\cdot mol^{-1}$ .

Apply the formula $\displaystyle n = \frac{m}{M}$ to find the number of moles of $\rm KCl$ and $\rm H_2O$ in this solution.

$\begin{aligned}n(\mathrm{KCl}) &= \frac{m(\mathrm{KCl})}{M(\mathrm{KCl})} \\ &= \frac{195.0\; \rm g}{74.6\; \rm g \cdot mol^{-1}} \approx 2.61\; \em \rm mol\end{aligned}$ .

$\begin{aligned}n(\mathrm{H_2O}) &= \frac{m(\mathrm{H_2O})}{M(\mathrm{H_2O})} \\ &= \frac{215\; \rm g}{18.0\; \rm g \cdot mol^{-1}} \approx 11.9\; \em \rm mol\end{aligned}$ .

The molar fraction of $\rm KCl$ in this solution would be:

$\begin{aligned} X_\mathrm{KCl} &= \frac{n(\mathrm{KCl})}{n(\text{All particles in this soluton})}\\ &= \frac{n(\mathrm{KCl})}{n(\mathrm{KCl}) + n(\mathrm{H_2O})} \\ &\approx \frac{2.61 \; \rm mol}{2.61\; \rm mol + 11.9\; \rm mol} \approx 0.180\end{aligned}$ .

(Rounded to three significant figures.)

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3 years ago

Mengapa dinding kapilari darah berbeza berbanding dinding vena dan arteri​

Mengapa dinding kapilari darah berbeza berbanding dinding vena dan arteri