Consider the equation for calculating molarity: (no. of mole of solute)÷(volume of solution)
First, let's find the no. of mole of solute in AgNO3. As (no. of mole) = mass / molar mass
no. of mole of 85.0g of AgNO3 = 85.0/(107.9+14.0+16.0x3)
=0.5mol
Since the volume of the solution has to be in dm3, just divide the volume in cm3 by 1000 to get the volume in dm3.
Volume of solution = 500/1000
= 0.5 dm3
Therefore, the molarity is
0.5/0.5
=1.0M
The answer should be B.
Answer:
decreases
Explanation:
the more conc of H ions increases the more it becomes acidic so the pH goes down
Answer:
The questions are incomplete
Explanation:
(b) This question is incomplete. However to calculate the number of moles of CuSO₄ present in the impure sample. The formula below can be used;
number of moles = mass of CuSO₄ present in the impure sample ÷ molar mass of CuSO₄
(c) This question is also incomplete. However, to calculate the mass percentage of CuSO₄ present in the impure sample of CuSO₄, the formula below can be used.
Mass percentage of CuSO₄ =
mass of CuSO₄ present in the impure sample/mass of impure CuSO₄ × 100
Thus, the mass of the impure sample must be measured also since the actual mass of the CuSO₄ present in the impure sample must have been measured before calculating the number of moles.
Answer:
The atomic number that should be here, 57, is located at the bottom of the table in the row called the Lanthanides. Directly below the space in Row 6, in Row 7, is another empty space, which is filled by a row called the Actinides, also seen at the bottom of the chart.
Explanation:
hope this helps!
