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Arturiano [62]
3 years ago
7

The Goodyear blimp we usually see hovering above our heads at a football game contains 5600 m3 of helium gas. If there are 1070

kg of gas at an absolute pressure of 1.10 105 Pa in the blimp, what is the temperature of the gas? The atomic mass of helium 4.00260 g/mol.
Chemistry
1 answer:
Alina [70]3 years ago
8 0

Answer:

277.16 K is the temperature of the gas.

Explanation:

Using ideal gas equation:

PV = nRT

where,

P = Pressure of gas = 1.10\times 10^5 Pa

V = Volume of gas = 5600 m^3

n = number of moles of gas = \frac{1,070 kg}{4.00260 g/mol}=\frac{1,070,000 g}{4.00260 g/mol}=267,326.24 mol

R = Gas constant = 8.314 J/mol.K

T = Temperature of gas = ?

Putting values in above equation, we get:

T=\frac{PV}{RT}

T=\frac{1.10\times 10^5 Pa\times 5,600 m^3}{267,326.24 mol\times 8.314 J/mol K}

T = 277.16 K

277.16 K is the temperature of the gas.

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During Photosynthesis , Plants Transforms Light Energy Into Chemical Energy .
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Consider the market for paper. Let market demand be given by inverse demand function P d (Q) = 60 − Q, where Q is tons of paper
MakcuM [25]

Answer:

See explaination

Explanation:

Demand for paper is given below:

P(Q)=60-Q,

Number of paper mills=20

The cost curve for firm is given below:

C(Q)=10Q2

The external cost in terms of pollution down river by production of paper is given below:

EC(Q)=10Q2

a. The optimal level of paper production by market can be calcuated by equating MC=P

20Q=P

Q=P/20

b. The optimal level of paper production by market can be calcuated by equating MC=P.

MC=20Q

60-(20Q)=20Q

Q=60/40

Q=1.5

Total quanity by 20 firms will be 1.5*20=30

c. The socially efficient level of paper output is calcuated below:

MC+EC'=20Q+20Q

60-(20Q)=40Q

Q=60/60

Q=1

Total quanity by 20 firms will be 1*20=20

The price will be P=60-20=40

d, The deadweight loss occurs as market price increases and quantity decreases due to the external cost . The deadweight loss is calcuated below:

DWL=(1/2)*change in price* change in quantity

=(1/2)*10*10=50

e. 20 firms merged into one firm to make monopoly firm. The cost function for the monopoly is given below:

Cm(Q)=20*10(Q/20)2

The marginal cost for the monopoly firm will be

MCm=Q

The marginal revenue for the firm is 60-2Q

For optimal output MR is equated to MC

60-2Q=Q

Q=20

P=40.

The monopoly outcome is below the perfect competition outcome and price is higher in comparison to perfect competition. The monopoly outcome is same as socially efficient outcome.

The total surplus for this outcome is sum of consumer surplus and producer surplus and subtraction of external cost

TS=CS+PS-EC

=(1/2)*20*20+(1/2)*40*20-10(20)2

=600-4000=-3400

Due to the external effects the total surplus to the society is negative. In perfect competition this effect is not considered and output produced is high therefore, the external cost will be higher with higher output leading to higher negative social surplus. Generally the monopoly outcome reduces the total social surplus but in case of externality, the monopoly total surplus is higher than the perfect competition.

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3 years ago
3. What agency tracks the activities of typhoon that enters PAR?
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Answer:

3.

D. Philippine Atmospheric, Geophysical and Astronomical Services

Administration (PAGASA)

Explanation:

4.C. 62.0 kph

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Alveoli are tiny sacs of air in the lungs. Their average diameter is 4.50 × 10−5 m. Calculate the uncertainty in the velocity of
Arisa [49]

<u>Answer:</u> The uncertainty in the velocity of oxygen molecule is 4.424\times 10^{-5}m/s

<u>Explanation:</u>

The diameter of the molecule will be equal to the uncertainty in position.

The equation representing Heisenberg's uncertainty principle follows:

\Delta x.\Delta p=\frac{h}{2\pi}

where,

\Delta x = uncertainty in position = d = 4.50\times 10^{-5}m

\Delta p = uncertainty in momentum  = m\Delta v

m = mass of oxygen molecule = 5.30\times 10^{-26}kg

h = Planck's constant = 6.627\times 10^{-34}kgm^2/s^2

Putting values in above equation, we get:

4.50\times 10^{-5}m\times 5.30\times 10^{-26}kg\times \Delta v=\frac{6.627\times 10^{-34}kgm^2/s}{2\times 3.14}\\\\\Delta v=\frac{6.627\times 10^{-34}kgm^2/s^2}{2\times 3.14\times 4.50\times 10^{-5}m\times 5.30\times 10^{-26}kg}=4.424\times 10^{-5}m/s

Hence, the uncertainty in the velocity of oxygen molecule is 4.424\times 10^{-5}m/s

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3 years ago
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