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4 years ago

Why do most coastal regions have two high tides and two low tides?

Physics

1 answer:

Dovator [93]4 years ago

7 0

Because the Earth rotates through two tidal bulges every lunar day.

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1) Why do the different rocks exposed in the Grand Canyon appear in layers for the most part? Where are the oldest layers of roc

fiasKO [112]

This is what i put:

<span> The Grand Canyon is made up of sedimentary rock; over time, sediments formed into layers. The layers on the bottom are the oldest, and the layers on the top are the youngest and newest.

Try and paraphrase though</span>

5 0

3 years ago

A boy is pulling a wagon with a force of 70.0 N directed at an angle of 30 degrees above the horizontal. What are the x and y co

bogdanovich [222]

Answer:

x component is 60.60 N and y component is 35 N ⇒ answer A

Explanation:

A boy is pulling a wagon with a force of 70.0 N directed at an angle

of 30 degrees above the horizontal then,

$F_{x}$ is the horizontal component of the force in the direction

of positive part of x-axis

$F_{y}$ is the vertical component of the force force in the direction

of positive part of y-axis

The x component of the force $F_{x}$ is the force multiplied by

cos(30)°

The y component of the force $F_{y}$ is the force multiplied by

sin(30)°

→ The x component $F_{x}$ = F cos(30)

→ The x component $F_{x}$ = 70 cos(30) = 60.60 N

→ The y component $F_{y}$ = F sin(30)

→ The y component $F_{y}$ = 70 sin(3) = 35 N

<em>x component is 60.60 N and y component is 35 N</em>

7 0

4 years ago

A car is traveling at 104 km/h when the driver sees an accident 50 m ahead and slams on the brakes. What minimum constant decele

Solnce55 [7]

Answer:

–8.35 m/s²

Explanation:

We'll begin by converting 104 km/h to m/s. This can be obtained as follow:

3.6 Km/h = 1 m/s

Therefore,

104 km/h = 104 km/h × 1 m/s / 3.6 Km/h

104 km/h = 28.89 m/s

Thus, 104 km/h is equivalent to 28.89 m/s.

Finally, we shall determine the deceleration of the car. This can be obtained as follow:

Initial velocity (u) = 28.89 m/s

Final velocity (v) = 0 m/s

Distance (s) = 50 m

Deceleration (a) =?

v² = u² + 2as

0² = 28.89² + (2 × a × 50)

0 = 834.6321 + 100a

Collect like terms

0 – 834.6321 = 100a

–834.6321 = 100a

Divide both side by 100

a = –834.6321 / 100

a = –8.35 m/s²

Thus, the deceleration of the car is –8.35 m/s².

5 0

3 years ago

When 15 newtons of force is applied to the 0.5 kg book, the friction keeps the book from sliding down the wall. What is the mini

valkas [14]

Answer:

15 N and 3.061

Explanation:

From the question,

The minimum force of friction to keep the book from sliding = 15 N.

using

F = mgμ................. Equation 1

Where F = Frictional Force, m = mass of the book, g = acceleration due to gravity, μ = coefficient of friction.

make μ the subject of the equation

μ = F/mg............... Equation 2

Given: F = 15 N, m = 0.5 kg, g = 9.8 m/s²

Substitute into equation 2

μ = 15(0.5×9.8)

μ = 15/4.9

μ = 3.061

Hence the coefficient of friction to keep the book from sliding = 3.061

4 0

4 years ago

Read 2 more answers

Federal board paper of class 10 of physics

zzz [600]

Answer:

If you are looking for past papers you can search that up and you will find plenty of resources that will help you out.

8 0

3 years ago