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VladimirAG [237]
3 years ago
3

A main sequence star does not expand or contract due to the balance between the internal heat pushing outward and the weight of

the material pressing inward due to gravity. This state of maintaining a constant size is known as:
hydrostatic equilibrium

thermal equilibrium

dynamic equilibrium
Physics
2 answers:
Basile [38]3 years ago
4 0

The correct answer to this question is hydrostatic equilbrium

A main sequence star is always under two equal and self regulating force acting in opposite direction.These are named as force of gravity and pressure due to internal heat.

The star has its own gravity which is destabilizing in nature.It tries to compress the star.It acts in vertically downward direction.

Due to the force of gravity,the star might have collapsed into a black hole which is not happening exactly.The star produces its energy from fusion reaction where hydrogen is converted into helium.In this reaction,much more amount of heat is produced.This increases the internal pressure pushing the star in outward direction.The outward pressure and the inward force of gravity balance each other.

Due to this the balance a hydrostatic equilibrium is maintained inside the star.


lora16 [44]3 years ago
3 0

Answer: Hydrostatic equilibrium

A main sequence star is a stable one. There is no overall change. This is because the gravity  of the material acting inward is balanced by the pressure gradient of the fluid acting outward. The star is made of gases. Its a fluid system. This kind of equilibrium is known as hydro-static equilibrium.

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To develop this problem we will apply the Archimedes model. As well as the definitions of Weight based on mass and acceleration. The first in turn will be considered under the relationship of Density and Volume. From the values given we have to:

\rho_w =1 g/mL \rightarrow \text{Water Density}

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Since it is in equilibrium, the weight of the object will have a reaction from the water, which will cause the sum of forces between the two objects to be zero, therefore

\sum F= 0

F_w-F_o = 0

F_w = F_o

m_w g = m_og

\rho_w V_w g = \rho_o V_o g

The value of gravity is canceled because it is a constant

\frac{V_w}{V_o} = \frac{\rho_o}{\rho_w}

\frac{V_w}{V_o} = \frac{0.82}{1}

\frac{V_w}{V_o} = 0.82

The portion of the object that is submerged corresponds to 82%, while the portion that is visible, above the water level will be 18%

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With the above formula, we can obtain th acceleration of the body as follow:

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