Answer:
Yes it will slide down the ramp
Explanation:
Let m be the mass of the box and gravitational acceleration g = 9.81m/s2, we can calculate the gravity that affects the box
W = mg
When the box is at 35 degree incline, this gravity is split into 2 components, 1 parallel to the incline (Wsin35) and the other one perpendicular with the incline (Wcos35).
The one perpendicular with the incline has an equal and opposite normal force of Wcos35
This normal force would dictate the static friction force where coefficient = 0.5. So the static friction is 0.5mgcos35
The box would slide when the parallel component of gravity wins over static friction force
mgsin35 > 0.5mgcos35
Since mg is positive we can cancel them out on both sides
sin35 > 0.5cos35
0.57 > 0.5*0.82
0.57 > 0.41
This is true so we can conclude that the box slides down the ramp
Answer:
Explanation:
distance walked
5000 + 3000 + 1000 = 9000 m
time taken to do the walk
9000 m / 1 m/s = 9000 s
magnitude of displacement during the walk
d = √((5000 - 1000)² + 3000²) = 5000 m
direction of displacement
θ = arctan(3000/4000) = 36.869897...°
velocity
v = d/t = 5000 m / 9000 s = 0.5556 m/s 36.87° N of E
Answer:
Option A is correct.
Bug A is experiencing a greater radial acceleration than Bug B.
Explanation:
The two bugs have the same angular speed, w, but different radii of the circular motion.
Bug A is closer to the edge of the turntable and bug B is farther from the edge of the turntable.
Hence, Bug A has a bigger radius of circular motion, hence, its radius can be called R and the radius of the circular motion for bug B is r.
v = wr
The radial acceleration of a body in circular motion is given as
α = (v²/r) = rw²
Radial acceleration for bug A = Rw²
Radial acceleration for bug B = rw²
Since we established that R > r and the angular speeds are equal,
Rw² > rw²
Hope this Helps!!!
The answer would be Inertia. Inertia is the tendency for an object to stay at its state of motion. Newton's 2nd law states that that an object in motion tends to stay in motion unless an external force acts upon it.