Set up the problem with the conversion rates as fractions where when you multiply the units cancel out leaving the desired units behind.
What is the external-internal pressure difference when the diver's lungs are at a depth of 6.1m (about 20ft)? assume that the di
1 answer:
Snorkel connects the diver's lungs with the air above the water. Because of this, the pressure inside the diver's lungs is the same as the atmospheric pressure.
The static pressure of a fluid is given with this equation:
The density of water is 1000kg/m^3.
Standart atmospheric pressure is 101<span>325Pa.
</span>The difference is:
The static pressure of a fluid is given with this equation:
The density of water is 1000kg/m^3.
Standart atmospheric pressure is 101<span>325Pa.
</span>The difference is:
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Answer:
Explanation:
-The chemical formula for Molybdenum (V) Dichromate is
-There are 21 moles of oxygen per one mole of Molybdenum (V) Dichromate
-We apply Avogadro's constant to find the number of atoms of oxygen:
Hence, there are
Answer:
It's only 1.11 m/s2 weaker at 400 km above surface of Earth
Explanation:
Let Earth radius be 6371 km, or 6371000 m. At 400km above the Earth surface would be 6371 + 400 = 6771 km, or 6771000 m
We can use Newton's gravitational law to calculate difference in gravitational acceleration between point A (Earth surface) and point B (400km above Earth surface):
where G is the gravitational constant, M is the mass of Earth and r is the distance form the center of Earth to the object
So the gravitational acceleration at 400km above surface is only 0.885 the gravitational energy at the surface, or 0.885*9.81 = 8.7 m/s2, a difference of (9.81 - 8.7) = 1.11 m/s2.