What is the external-internal pressure difference when the diver's lungs are at a depth of 6.1m (about 20ft)? assume that the di
1 answer:
Snorkel connects the diver's lungs with the air above the water. Because of this, the pressure inside the diver's lungs is the same as the atmospheric pressure.
The static pressure of a fluid is given with this equation:
The density of water is 1000kg/m^3.
Standart atmospheric pressure is 101<span>325Pa.
</span>The difference is:
The static pressure of a fluid is given with this equation:
The density of water is 1000kg/m^3.
Standart atmospheric pressure is 101<span>325Pa.
</span>The difference is:
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Answer:
D. Frequency
Explanation:
The energy of an electromagnetic wave is proportional to frequency, mathematically it is expressed as;
E ∝ f
E = hf
where;
h is Planck's constant = 6.626 x 10⁻³⁴ Js
The equation above can also be expanded to;
where;
c is speed of light = 3 x 10⁸ m/s
λ is the wavelength of the electromagnetic wave
Since the speed of light is constant, we can conclude that the energy of the electromagnetic wave is directly proportional to its frequency and inversely proportional to its wavelength.
Therefore, the correct option for direct proportionality is FREQUENCY