For #5 It's helpful to draw a free body diagram so you know which way the forces are acting on the block.
the weight mg is acting downwards, and you need to find the vertical and horizontal components of mg using sin and cosine. so do 15x9.8xsin40 which is the force. Assuming no friction, this is the only force acting on the block, as the forces on the vertical plane cancel out i.e the normal force and weight of the block.
after, just do F=ma And since you know F and m, solve for a.
Answer: (B) There is complete destructive interference between the incoming and reflected waves
Explanation:
For example, if you pluck a guitar the waves will travel back and forth. They consist of nodes and anti-nodes. It is created, when the wave traveling to one side and bounces of the other end and comes back. As it travels to the other side, it is reflected thus, comes back. So standing waves occurs when there is interference.
When the wave is produced, the points where the string is not moving are called nodes and where they are moving are called anti-nodes. The positions where nodes are produced, destructive interference occurs and where anti-nodes are produced, constructive interference occurs
Answer:
14 N
Explanation:
The tension in the second string is puling both the masses of 20 kg and 8 kg with acceleration of 0.5 m s⁻²
So tension in the second string = total mass x acceleration
= 28 x .5 = 14 N . Ans..
Answer:
0.532
Explanation:
Your equation to find the second bright interference maximum is gonna be this: d sin (Θ) = m λ
First, find your variables.
λ = 580 · 10^-9
d = 0.000125
m = 2
Next, fill in the equation.
d sin (θ) = m λ
(0.000125) sin (θ) = (2) (580·10^-9)
Then isolate your variable.
θ = arcsin ( (2)(580·10^-9) / (0.000125) )
Run your equation and you will end up with 0.53171246 , which rounds to 0.532.
The main thing you have to watch out for is make sure you are calculating for the bright interference and not the dark interference, as well as checking you're calculating for the maximum, not the minimum.
I hope this helps :D
What you want.. you would need to post your question
