Question

I NEED A QUESTION ON THE CONSERVATION OF MECHANICAL ENERGY AND THE ANSWER PLEASE

Answer 1

Answer:

See Below

Explanation:

Question:

A 200 g dart is pressed against the spring of a toy dart gun. The spring (with spring constant k = 500 N/s) is compressed by 6.0 cm and released. If the dart detaches from the spring when the spring reaches its equilibrium length (x = 0), what is the launch speed of the dart?

Answer:

PE = KE

1/2kx^2 = 1/2mv^2

Sole for v:

v = sqrt(kx^2/m)

v = sqrt(500*(0.06)^2/0.200)

v = sqrt(1.8/0.200

v = sqrt(9)

v = 3 m/s

I really hoped this helped you. :) Sorry if it didn't.