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OLga [1]
3 years ago
5

I NEED A QUESTION ON THE CONSERVATION OF MECHANICAL ENERGY AND THE ANSWER PLEASE

Physics
1 answer:
zavuch27 [327]3 years ago
3 0

Answer:

See Below

Explanation:

Question:

A 200 g dart is pressed against the spring of a toy dart gun. The spring (with spring constant k = 500 N/s) is compressed by 6.0 cm and released. If the dart detaches from the spring when the spring reaches its equilibrium length (x = 0), what is the launch speed of the dart?

Answer:

PE = KE

1/2kx^2 = 1/2mv^2

Sole for v:

v = sqrt(kx^2/m)

v = sqrt(500*(0.06)^2/0.200)

v = sqrt(1.8/0.200

v = sqrt(9)

v = 3 m/s

I really hoped this helped you. :) Sorry if it didn't.

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Choose the statement(s) that is/are true about the ratio \frac{C_p}{C_v} C p C v for a gas? (Ii) This ratio is the same for all
Blababa [14]

Answer:

(i) false

(ii) true

(iii) true

(iv) false

Explanation:

(i) The ratio of Cp and Cv is not constant for all the gases. It is because the value of cp and Cv is different for monoatomic, diatomic and polyatomic gases.

So, this is false.

(ii) For monoatomic gas

Cp = 5R/2, Cv = 3R/2

So, thier ratio

Cp / Cv = 5 / 3 = 1.67

This statement is true.

(iii) for diatomic gases

Cp = 7R/2, Cv = 5R/2

Cp / Cv = 7 / 5 = 1.4

This statement is true.

(iv) It is false.

6 0
4 years ago
Which planet has the most gravity and why
djyliett [7]

heya mate

the planet Jupiter has most gravity due to its size

7 0
3 years ago
Read 2 more answers
27 degrees to kelvin, 20 dg to milligrams, and 3 to decimeters.
Gala2k [10]
K = C + 273, so 27°C = 27+273 = 300 K

1 dg = 100 mg, so 20 dg = 20×100 = 2,000 mg
7 0
3 years ago
You throw a rock horizontally out of a 7th story window. You time that it takes 3.7 seconds to hit the ground, and measure that
Nady [450]
Since we are only looking at the vertical height, we can use the free fall equation to find the height:
h = 0.5*g*t^2, where h is height in m, g is acceleration due to gravity (9.81 m/s^2), and t is time in seconds
h = 0.5*(9.81 m/s^2)*(3.7 s)^2
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5 0
3 years ago
a mass of 0.75 kg is attached to a spring and placed on a horizontal surface. the spring has a spring constant of 180 N/m, and t
Artemon [7]

Answer:

6.57 m/s

Explanation:

First use Hook's Law to determine the F the compressed spring acts on the mass. Hook's Law F=kx; F=force, k=stiffnes of spring (or spring constant), x=displacement

F=kx; F=180(.3) = 54 N

Next from Newton's second law find the acceleration of the mass.

Newton's .2nd law F=ma; a=F/m ; a=54/.75 = 72m/s²

Now use the kinematic equation for velocity (or speed)

v₂²= v₀² + 2a(x₂-x₀); v₂=final velocity; v₀=initial velocity; a=acceleration; x₂=final displacement; x₀=initial displacment.

v₀=0, since the mass is at rest before we release it

a=72 m/s² (from above)

x₀=0 as the start position already compressed

x₂=0.3m (this puts the spring back to it's natural length)

v₂²= 0 + 2(72)(0.3) = 43.2 m²/s²

v₂=\sqrt{43.2)\\ = 6.57 m/s

5 0
3 years ago
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