4. What are 3 things that you can think of doing, that would reduce your electricity bill?

1 answer:

3 0

Turn off standby appliances.
Install a smart thermostat.
Turn down your thermostat.
Buy efficient appliances.
Install a new boiler.
Wash clothes at a lower temperature.
Be smarter about water.
Invest in double glazing.

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A snowmobile has an initial velocity of 3.0 m/s

dexar [7]

My answer to the problem is as follows:

<span>1. Use the kinematic formula

Vf = Vi + a*t

for a, Vi = 3.0 m/s, a = 0.5 m/s/s, and t = 7.o s.

for b, Vf = 0, Vi = 3.0 m/s, and a = -0.60 m/s/s.

I hope my answer has come to your help. God bless and have a nice day ahead!
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Push a notebook or some other object so that it slides across a table or desktop. What force causes the notebook to start moving

Tju [1.3M]

Answer:

Kinetic force

Explanation:

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3 years ago

What is the maximum force that could be applied to anterior cruciate ligament (ACL) if it has a diameter of 4.8 mm and a tensile

vovangra [49]

Answer:

Maximum force, F = 1809.55 N

Explanation:

Given that,

Diameter of the anterior cruciate ligament, d = 4.8 mm

Radius, r = 2.4 mm

The tensile strength of the anterior cruciate ligament, $P=100\times 10^6\ N/m^2=10^8\ Pa$

We need to find the maximum force that could be applied to anterior cruciate ligament. We know that the unit of tensile strength is Pa. It must be a type of pressure. So,

$F=P\times A\\\\F=10^8\times \pi (2.4\times 10^{-3})^2\\\\F=1809.55\ N$

So, the maximum force that could be applied to anterior cruciate ligament is 1809.55 N

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What accurately describes the relationship between brain damage and language impairment?

nirvana33 [79]

The level and type of impairment determine the severity and location of the injury.

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It takes 185 kj of work to accelerate a car from 23.0 m/s to 28.0 m/s. what is the car's mass?

Pachacha [2.7K]

<span>This question is based on conservation of energy as the work done would lead to change in kinetice energy of car change in KE = 1/2 mv(f)^2 - 1/2mv(i)^2 = 1/2m(v(f)^2-v(i)^2) where v(f) and v(i) are the final and initial speeds change in KE = 185kJ = 185,000J = 1/2 m((28m/s)^2-(23m/s)^2) 185,000=1/2 m(255m^2/s^2) solving for m m=1451kg</span>

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3 years ago