The final velocity of the two pucks is -5 m/s
Explanation:
We can solve the problem by using the law of conservation of momentum.
In fact, in absence of external force, the total momentum of the two pucks before and after the collision must be conserved - so we can write:

where
is the mass of each puck
is the initial velocity of the 1st puck
is the initial velocity of the 2nd puck
v is the final velocity of the two pucks sticking together
Re-arranging the equation and solving for v, we find:

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B strength training I think that’s the answer
Answer:
V = 0.0806 m/s
Explanation:
given data
mass quarterback = 80 kg
mass football = 0.43 kg
velocity = 15 m/s
solution
we consider here momentum conservation is in horizontal direction.
so that here no initial momentum of the quarterback
so that final momentum of the system will be 0
so we can say
M(quarterback) × V = m(football) × v (football) ........................1
put here value we get
80 × V = 0.43 × 15
V = 0.0806 m/s
Answer:
The solution set of a disjunction is the union of the solution sets of the individual inequalities. A convenient way to graph a disjunction is to graph each individual inequality above the number line, then move them both onto the actual number line
Explanation:
Answer: The velocity is 21.5m/s
Explanation:
Let's call:
M1 and V1 as the mass and velocity of the falcon:
M1 = 1.45kg
V1 = 26.5m/s
M2 and V2 as the mass and velocity of the dove:
M2 = 0.415kg
V2 = 4.35m/s
Where both velocities are positive because both animals move in the same direction.
We can think that the interaction between both animals is a perfectly inelastic collision, because afther the interaction they move as one. Then, we have that the final velocity of both animals togheter is:
V = (V1*M1 + V2*M2)/(M1 + M2)
V = (1.45kg*26.5m/s + 0.415kg*4.35m/s)/(1.45kg + 0.415kg) = 21.5m/s