1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
PtichkaEL [24]
3 years ago
14

Consider a blackbody that radiates with an intensity i1 at a room temperature of 300k. At what intensity i2 will this blackbody

radiate when it is at a temperature of 400k?
Physics
1 answer:
alexgriva [62]3 years ago
4 0

Answer:

3.16 i1

Explanation:

T1 = 300 k

I1 = i1

T2 = 400 k

i2 = ?

The intensity is directly proportional to the four powers of the absolute temperature.

I ∝ T^4

So, \frac{i_{2}}{i_{1}}=\frac{T_{2}^{4}}{T_{1}^{4}}

\frac{i_{2}}{i_{1}}=\frac{400^{4}}{300^{4}}

i2 = 3.16 i1

Thus, the intensity becomes 3.16 i1.

You might be interested in
What can be known about the density of sodium
lesya692 [45]
D? maybe i’m trying to. see if it’s d or b
4 0
3 years ago
Read 2 more answers
The term ampacity is defined as the _____ current, in amperes, that a conductor can carry continuously under conditions of use w
White raven [17]

Answer:

The maximum current, in amperes, that a conductor can carry continuously under the conditions of abuse without exceeding its temperature rating.

5 0
3 years ago
HELP ASAP PLS. ILL GIVE BRAINLIEST
Blizzard [7]

Answer:

I'm not completely sure, but I believe the first and third of the three are mechanical.

Explanation:

Chemical potential isn't moving or about to go into motion. It can't be mechanical.

4 0
3 years ago
Is cutting a string physcal or chemical change
oksano4ka [1.4K]
This is a physical change because cutting the string didn't change it chemically, but it did physically.
6 0
3 years ago
A magnetic field of magnitude 0.550 T is directed parallel to the plane of a circular loop of radius 43.0 cm. A current of 5.80
Assoli18 [71]

Answer:

\mu = 3.36\times 10^{-3}\ A-m^2

Explanation:

Given that,

The magnitude of magnetic field, B = 0.55 T

The radus of the loop, r = 43 cm = 0.43 m

The current in the loop, I = 5.8 mA = 0.0058 A

We need to find the magnetic moment of the loop. It is given by the relation as follows :

\mu = AI\\\\\mu=\pi r^2\times I

Put all the values,

\mu=\pi \times (0.43)^2\times 0.0058\\\\=3.36\times 10^{-3}\ A-m^2

So, the magnetic moment of the loop is equal to3.36\times 10^{-3}\ A-m^2.

3 0
3 years ago
Other questions:
  • How did Thompson´s model differ from Dalton´s model
    15·1 answer
  • What did Dr. Kidwell's fighting so the birds eating a box on different tree trunks
    5·1 answer
  • 1. How is it possible to use pools to model apparent weightlessness, similar to what astronauts
    8·1 answer
  • Suppose that the mirror described in Part A is initially at rest a distance R away from the sun. What is the critical value of a
    10·1 answer
  • If the magnitude of a positive charge is tripled, what is the ratio of the original value of the electric field at a point to th
    6·1 answer
  • Which of the following describes a major role of gravity in star formation?
    12·2 answers
  • PLEASE HELP WILL NAME BRAINLIEST!! An object is dropped from rest. What is its instantaneous speed when it has been in motion fo
    11·1 answer
  • A wooden block has a volume of 12 cm3 and a density of 3 g/cm3. What is the mass of the wooden block?
    8·2 answers
  • How is a magnetic field generated?
    10·2 answers
  • Which of the following statements describes an interaction between the geosphere and biosphere?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!