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Rudiy27
3 years ago
15

Ben observes how quickly some dry wood is burning in a campfire. which term best relates to ben's observation?

Chemistry
2 answers:
Katyanochek1 [597]3 years ago
7 0
I think this the the list of choices relating to the above question.
reaction rate 
<span>activation energy </span>
<span>collision theory </span>
<span>spontaneous reaction
</span>
The term that best relate to ben's observation is REACTION RATE.

Reaction rate is defined as the speed at which the chemical reaction proceeds. It either is the amount of concentration of a product in a given unit of time or the concentration of the reactant that is being consumed in a unit of time.
Likurg_2 [28]3 years ago
6 0

Answer:

i just took the ed-genuity quiz and the answer is a) reaction rate

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What are protons explained simply
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The protons inside an atom's nucleus help bind the nucleus together. They also attract the negatively charged electrons, and keep them in orbit around the nucleus. The number of protons in an atom's nucleus determines which chemical element it is.

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Match the salt with the acid and base used to form it in a neutralizing reaction.
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<h3><u>Answer;</u></h3>

K2SO4 - KOH and H2SO4

NaBr - NaOH and HBr

<h3><u>Explanation;</u></h3>
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  • Salts may be produced when acids and bases are combined together in equal proportions, a process called neutralization.
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Arrange the following H atom electron transitions in order of decreasing wavelength of the photon absorbed or emitted:
Katyanochek1 [597]

The decreasing order of wavelengths of the photons emitted or absorbed by the H atom is : b → c → a → d

Rydberg's formula :

                                   \frac{1}{\lambda} = R_h (\frac{1}{n_1^2}-\frac{1}{n_2^2} ),

where  λ is the wavelength of the photon emitted or absorbed from an H atom electron transition from n_1 to n_2 and R_h = 109677 is the Rydberg Constant. Here n_1 and  n_2 represents the transitions.

(a) n_1 =2 to n_2 = infinity

            \frac{1}{\lambda} = 109677\times (\frac{1}{2^2}-\frac{1}{\infty^2}  ) = 109677/4     [since 1/infinity = 0] Therefore, \lambda = 4 / 109677 = 0.00003647 m

(b) n_1=4 to  n_2 = 20

           \frac{1}{\lambda} = 109677\times (\frac{1}{4^2}-\frac{1}{20^2}  ) = 6580.62

Therefore,  \lambda = 1 / 6580.62 = 0.000152 m

(c) n_1=3 to  n_2 = 10

          \frac{1}{\lambda} = 109677\times (\frac{1}{3^2}-\frac{1}{10^2}  ) = 11089.56

Therefore,  \lambda = 1 / 11089.56 = 0.00009 m

(d)  n_1=2 to  n_2 = 1

          \frac{1}{\lambda} = 109677\times (\frac{1}{2^2}-\frac{1}{1^2}  ) = - 82257.75

Therefore,  \lambda = 1 /82257.75  = - 0.0000121 m  

[Even though there is a negative sign, the magnitude is only considered because the sign denotes that energy is emitted.]

So the decreasing order of wavelength of the photon absorbed or emitted is b → c → a → d.

Learn more about the Rydberg's formula athttps://brainly.com/question/14649374

#SPJ4

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1 year ago
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that is why co2 is in the power of 2ik

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Plants don't need sap. They make it like Maple trees.
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