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3 years ago

NH3 + H2O How do I balance this

Chemistry

1 answer:

Alla [95]3 years ago

5 0

Answer:

NH3 +H2O = NH4OH

Explanation:

no.of N atoms,O atoms and H atoms are now equal on both sides of the arrow.

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Calculate the ph of a dilute solution that contains a molar ratio of potassium acetate to acetic acid (pka ???? 4.76) of (a) 2:1

givi [52]

According to Hasselbach-Henderson equation:

$pH=pK_{a}+log\frac{[A^{-}]}{[HA]}$

Here, $[A^{-}]$ is concentration of conjugate base and [HA] is concentration of acid.

In the given problem, conjugate base is $CH_{3}COOK$ and acid is $CH_{3}COOH$ thus, Hasselbach-Henderson equation will be as follows:

$pH=pK_{a}+log\frac{[CH_{3}COOK]}{[CH_{3}COOH]}$ ...... (1)

(a) Ratio of concentration of potassium acetate and acetic acid is 2:1 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=2$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{2}{1}=5.06$

Therefore, pH of solution is 5.06.

(b) Ratio of concentration of potassium acetate and acetic acid is 1:3 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=\frac{1}{3}$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{1}{3}=4.28$

Therefore, pH of solution is 4.28.

(c)Ratio of concentration of potassium acetate and acetic acid is 5:1 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=\frac{5}{1}$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{5}{1}=5.45$

Therefore, pH of solution is 5.45.

(d) Ratio of concentration of potassium acetate and acetic acid is 1:1 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=1$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{1}{1}=4.76$

Therefore, pH of solution is 4.76.

(e) Ratio of concentration of potassium acetate and acetic acid is 1:10 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=\frac{1}{10}$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{1}{10}=3.76$

Therefore, pH of solution is 3.76.

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3 years ago

Match the academic requirements with the careers . Cosmetologist

inessss [21]

Answer:

Technical program - cosmetologist

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4 years ago

What might happen if the strong force didnt exist

topjm [15]

If the strong force didn't exist, there would be nothing but hydrogen and neutrons floating in space. ... When the protons and neutrons are apart there is no strong force but when they are together to resemble a nucleus, the strong force is in action.

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3 years ago

Read 2 more answers

Pls help me with is question.

Dennis_Churaev [7]

Answer:

25cm³ = 0.025L of H2So4

Molarity of H2SO4 = 1moldm-³

Recall ... 1dm-³ = 1L

So the Molarity can also be 1mol/L

Mole = Molarity x volume in L

Mole of H2SO4 = 1mol/L x 0.025L

=0.025Moles of Sulphuric acid reacted.

From the equation of reaction

1mole of H2SO4 reacts to produce 1mole of Copper sulphate crystal

Since their Mole ratio is 1:1

It means that Since 0.025mole of H2SO4 reacted.... 0.025mole of CuSO4.5H2O would be produced

Nice.. OK

So we know the moles of CuSO4.5H2O produced

We can get the Mass

Recall

From

Mole=Mass/Molar Mass

Mass = Mole x Molar Mass

Molar Mass of CuSO4.5H2O = 64 + 32 + 16x4+ 5(2+16)

Mm= 250g/mol

Mass = 0.025mol x 250g/mol

= 6.25g of CuSO4.5H2O crystals Would be PRODUCED.

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3 years ago

Why do so many of earths volcanoes occur along plate boundaries

OverLord2011 [107]

Because of the plates crashing into each other

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3 years ago