Answer:
7.52 × 10⁻¹⁴ mi
Explanation:
Step 1: Given data
Bond length between two carbon atoms (l): 121 pm
Step 2: Convert "l" to meters
We will use the conversion factor 1.00 m = 1.00 × 10¹² pm.
121 pm × (1.00 m / 1.00 × 10¹² pm) = 1.21 × 10⁻¹⁰ m
Step 3: Convert "l" to miles
We will use the conversion factor 1.00 mi = 1609.34 m.
1.21 × 10⁻¹⁰ m × (1.00 mi / 1609.34 m) = 7.52 × 10⁻¹⁴ mi
Answer:
Sn2 mechanism reaction
Explanation:
In this case, we have a <u>primary substrate</u> (1-bromo-3,3-dimethylbutane). Because the <u>leaving grou</u>p "Br" is bonded to a <u>primary carbon</u>. Additionally, the nucleophile will come from the "NaI" (sodium iodide). This is an <u>ionic compound</u>, so, in solution, a cation and an anion would be produced. The anion
would be the <u>nucleophile</u>.
Due to the primary substrate, we will have an <u>Sn2 reaction</u>. So, the attack of the nucleophile and the removal of the leaving group will take place in <u>1 step</u>. Producing a <u>"transition state"</u> and finally and the final product (1-iodo-3,3-dimethylbutane).
See figure 1
I hope it helps!
Multiply velocity and time and you get 0.644 km, but remember that displacement has a direction and so does velocity, so because velocity is positive in the direction that the falcon is going you have a positive displacement.
Moles of lead(Pb) = 1.6x10^23/6.02x10^23 = 0.265 moles.
Weight of lead = moles x atomic weight of lead
= 0.265x207.2
= 54.908 grams.
Hope this helps!
Answer:
See balanced equations below
Explanation:
1. Mg(s) +2 HCL (aq) →MgCl₂ (aq) +H₂(g)
This is a single replacement reaction, involving an acid with a metal
2. 2Al(s) + 3H₂SO₄ (aq)→Al₂(SO₄)₃(aq) + 3H₂
3. 3 Zn (s) + 2H₃PO₄(aq)→ Zn₃(PO₄)₂ (aq) + 3H₂ (g)
4. 2Al(s) + 6HCL (aq)→2AlCl₃(aq) +3H₂ (g)
B.
1. 2KOH(aq) + MgCl₂→Mg(OH)₂ (aq) + 2KCl (aq)
2. 3NaOH (aq)+ Al(NO₃)₃ (aq)→Al(OH)₃(s) + 3 NaNO₃(aq) ---this is a precipitation reaction
3. BaBr₂(aq) + H₂SO₄→BaSO₄ (s) + 2Br⁻(aq)
4. Na₂S + 2HCl → 2NaCl (aq) + H₂S (g)
5. 3CaCl₂ +2K₃PO₄→ Ca₃(PO₄)₂+6KCl
6.Ba(NO₃)₂ + (NH₄)₂CO₃→ 2(NH₄)⁺(aq) +BaCO₃(s)