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Ugo [173]
3 years ago
12

An analytical chemist is titrating of a solution of propionic acid with a solution of . The of propionic acid is . Calculate the

pH of the acid solution after the chemist has added of the solution to it.
Chemistry
1 answer:
motikmotik3 years ago
3 0

Answer:

Heres my attempt at this and hope it helps friend

.1372L * (.83M/L) = .114 mols propanoic acid

.06862L * (1.1M/L) = 0.0755 mols NaOH

using the henderson hasselbach equation

ph = pKa + log([A-]/[HA])

so

ph = 4.89 + log(.0755/.114) = 4.72

Explanation:

Identify at least three reasons the Articles of Confederations failed as a governing document. In your opinion, evaluate which defect was most debilitating, using evidence and your knowledge of American government to justify your position.

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Mama L [17]

Answer:

A

Explanation:

3 CARBON ATOMS 8 HYDROGEN

5 0
3 years ago
Transfer 2-3 drops of each solution onto the indicator paper. Be sure to
alexira [117]

Answer:

0.1 M HCl pH: 1-2

0.001 M HCl pH: 3-4

0.00001 M HCl pH: 5-6

Distilled Water pH: 7

0.00001 M NaOH pH: 8-9

0.001 M NaOH pH: 10-11

0.1 M NaOH pH: 12-13

Explanation:

4 0
3 years ago
What is the difference in mass between 3.01×10^24 atoms of gold and a gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm
Zanzabum

Answer:

The difference in mass between 3.01×10^24 atoms of gold and a gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm is :

<u>Difference</u>  <u>in mass</u> =<u> 985.32 - 984.5 = 0.82 g</u>

Explanation:

<u>Part I :</u>

n =\frac{3.01\times 10^{24}}{6.022\times 10^{23}}

n = 4.9983

n = 4.99 moles

(Note : You can also take n = 5 mole )

Molar mass of gold = 196.96 g/mole

This means, 1 mole of gold(Au) contain = 196.96 grams

So, 4.99 moles of gold contain = 5\times 196.96 g

4.99 moles of gold contain = 984.8 g

Mass of {3.01\times 10^{24}} atoms of gold = 984.5 g

<u>Part II :</u>

Density of Gold = 19.32 g/cm^{3}

Volume of the cuboid = length\times breadth\times height

Volume of the gold bar =6.00\times 4.25\times 2.00

Volume of the gold bar = 51cm^{3}

Using formula,

Density = \frac{mass}{Volume}

Mass = Density\times Volume

Mass = 19.32 \times 51

Mass = 985.32 g

So, A  gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm has mass of <u>985.32 g</u>

<u>Difference</u>  <u>in mass</u> =<u> 985.32 - 984.5 = 0.82 g</u>

3 0
3 years ago
Many types of scientific equipment are used to perform different functions in the science lab. Which of the following combinatio
Phantasy [73]
I guess B is the right one......
4 0
3 years ago
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which of the following requires the most energy to break a bond? a. breaking cl-br bond. b. breaking a n-p bond. c. breaking a o
irina1246 [14]

A. Breaking a Cl-Br bond

6 0
2 years ago
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