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AlladinOne [14]
3 years ago
11

If two negative charges decrease 1/2 times it's original charge then the force will become how many times stronger

Physics
1 answer:
vovangra [49]3 years ago
8 0
5! 5! 5! 5! it's 5!!!!!!!!!! Well that's what my friend told me so
You might be interested in
How much potential energy does a 40-N medicine ball gain when it is lifted 5 m?
777dan777 [17]
We know, Potential Energy = Force * Height
Here, F = 40 N
h = 5 m

Substitute their values, 
U = 40 * 5
U = 200 J

In short, Your Answer would be Option A

Hope this helps!
6 0
3 years ago
What would the speed of this wave be?
valentinak56 [21]

Answer:

c) 100,000 m/s

Explanation:

You need to take the same wave length from the top graph and bottom one, so let's take half a wave length then in the top one that is 0.005, but in the bottom one it's 2000/4 = 500 because they are smaller and there are 4 half waves before you get to 2000, whereas in the top one there is 1 half wave before you get to 0.005 on the graph.

Now use speed = distance / time

speed = 500 / 0.005 = 100 000 m/s

7 0
3 years ago
A uniform cylindrical grindstone has a mass of 15.0 kg and a radius of 18.6 cm. The grindstone reaches a rotational velocity of
tekilochka [14]

Answer:

n \approx 5.778\times 10^{-4}\,rev

Explanation:

The Work-Energy Theorem is applied herein:

-\frac{1}{4}\cdot m_{cyl}\cdot R^{2}\cdot \omega^{2} = - \mu_{k}\cdot N\cdot r \cdot 2\pi \cdot n

The number of turns needed to stop the grindstone is:

n = \frac{m_{cyl}\cdot R^{2}\cdot \omega^{2}}{4\cdot \mu_{k}\cdot N \cdot r\cdot 2\pi}

n = \frac{(15\,kg)\cdot (0.186\,m)^{2}\cdot [(1.83\,\frac{rev}{min} )\cdot (\frac{2\pi\,rad}{1\,rev} )\cdot (\frac{1\,min}{60\,s} )]^{2}}{4\cdot (0.80)\cdot (8.82\,N)\cdot(0.186\,m)\cdot 2\pi}

n \approx 5.778\times 10^{-4}\,rev

8 0
3 years ago
Project: weather forcasting
Paul [167]

B that is the correct answer

7 0
1 year ago
How far apart are a proton and electron if they exert an attractive force of 3n on one another
valina [46]

Answer:

     distance=8.76\times 10^{-5}angstrom

Explanation:

The <em>3N force </em>must be attributed to electrostatic attraction between both charges.

The formula is known as Coulomb's law:

    F_E=k\times \dfrac{q_1\cdot q_2}{d^2}

Where:

  • F_E is the elecrostatic force: 3 N
  • k is the constant  for Coulomb's law ≈ 9.00 × 10⁹ N . m² / C²
  • d is the distance that separate the centers of the charges
  • q_1\text{ and }q_2 are the values of the charges: ≈ ± 1.6 × 10⁻¹⁹ C

When you are not interested in the direction of the electrostatic force you just use the magnitudes of the charges.

Substitute in the formula and solve for d:

      3N=9.00\times 10^9N\cdotm^2/C^2\times\dfrac{(1.6\cdot 10^{-19}C)^2}{d^2}

      d=8.76\times 10^{-15}m^2

That can be converted to angstroms with the conversion factor:

  • 1m = 10¹⁰ angstrom

d= 8.76\times 10^{-15}m\times 10^{10}angstrom/m=8.76\times 10^{-5}angstrom

3 0
2 years ago
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