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SOVA2 [1]
3 years ago
15

Which example best shows conservation of resources?

Chemistry
2 answers:
Inessa05 [86]3 years ago
7 0

Answer:

Recycling aluminum cans and glass bottles

Elanso [62]3 years ago
6 0

Answer:

B. Recycling cans and glass bottles

Explanation:

This is actually really easy once you eliminate all the other answers which are competently incorrect and this answer choice is the best one available hope this helps. :)

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8. Zeolite is used to remove moisture from methane. A vertical column is filled with 1000.0 kg of dry zeolite. The zeolite has t
Natasha_Volkova [10]

Answer:

Follows are the solution to this question:

Explanation:

Methane inlet humidity content of =7.00\%

Methane moisture outlet content =0.05\%

Zeolite absorption humidity = 6.95\%

Dry zeolite 1 kg will accommodate water= 0.1000 \ kg

One kilogram of Dry Zeolite will carry water from =0.1000\ kg

The water can contain 1000 kg of zeolite = 100 \ kg

Methane which would be made =\frac{100}{6.95\%}= 1,439 \ kg

That's why it will be producing 1439 kg of methane.

3 0
3 years ago
Which of the following describes the characteristics of a solid?
LenaWriter [7]

A.

In a solid there is the least amount of room in between each particle and they are organized.

B. Is a liquid

C. I think it’s plasma but ik it is not a solid

D. Gas

6 0
3 years ago
Read 2 more answers
The equilibrium constant kc for the reaction hf(aq) + h2o(l) h3o+(aq) +f-(aq) is 3.5 x 10-4. what is the equilibrium concentrati
nataly862011 [7]
According to the reaction equation:
          Hf(aq) + H2O (l)↔ H3O+ (aq) + F(aq)  

initial   1 m                       0           0
            -X                         +X          +X
          (1-x)                         X            X
We assumed that [H3O+] = X
so. at eqilibrium:
Kc = [H3O] [ F] / [Hf] when we have Kc so by substitution:
3.5x10^-4 = X^2 / (1-X)
∴X^2 = 3.5x10^-4 - 3.5x10^-4 X
X^2 + 3.5x10^-4 X - 3.5x10^-4= Zero
by solving this equation:
(X-1.9x10^-2)(X + 1.9x10^-2) = Zero 
∴X = 1.9x10^-2 
∴ the equilibrium constatnt of H3O = 1.9x10^-2 M
5 0
3 years ago
A solution of H2SO4(aq) with a molal concentration of 4.80 m has a density of 1.249 g/mL. What is the molar concentration of thi
Naddika [18.5K]
Imagine we have <span>mass of solvent 1kg (1000g)
According to that: </span>molality =n(solute) / m(solvent) =\ \textgreater \  4.8m = 4.8mole / 1kg
= 4.8 mole * 98 g/mole = 470g
m(H2SO4) = n(H2SO4)*Mr(H2SO4) =\ \textgreater \=\ \textgreater \  Molarity = 4.8 mole / 1.2 L = 4 M m(H2SO4)  which is =<span>470g

</span><span>m(solution) = m(H2SO4) + m(solvent) = 470 + 1000 = 1470 g
d(solution) = m(solution) / V(solution) =>
=> 1.249 g/mL = 1470 g / V(solution) =></span>
Molarity = n(solute) / V(solution) =\ \textgreater \
5 0
3 years ago
The electronegativity of Na is 0.9;Cl is 3.0; where will their shared electron (NaCl)spend most of its time
barxatty [35]
Cl, because a higher electronegativity indicates that the atom attracts more electrons.
8 0
3 years ago
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