Answer:
Molarity of Ba²⁺ is 0M
Explanation:
Some barium ion, Ba²⁺ is produced when barium acetate is dissolved (Moles of barium acetate = moles of Ba²⁺ in solution). Then, Ba²⁺ reacts with sulfate ion to produce BaSO₄, an insoluble salt. The concentration of Ba²⁺ is the initial concentration - the concentration of SO₄²⁻ in solution.
Initial moles of Ba²⁺:
Moles barium acetate (Molar mass: 255.43g/mol)
0.363g * (1mol / 255.43) = 1.421x10⁻³ moles of Ba²⁺
Moles SO₄²⁻ = Moles of ammonium sulfate:
100mL = 0.100L * (0.025mol / L) = 2.5x10⁻³ moles of SO₄²⁻.
As moles of SO₄²⁻ are higher than moles of Ba²⁺, Molarity of Ba²⁺ is 0M because all moles of Ba²⁺ reacts producing BaSO₄(s), an insoluble salt.
