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Igoryamba
3 years ago
10

A ball is projected horizontally from the top of a cliff and free falls to the ground.

Physics
1 answer:
blagie [28]3 years ago
3 0
They will both land at the same time.
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You have probably noticed that carrying a person in a pool of water is much easier than carrying a person through air. To unders
Kruka [31]

Answer:

The answer is "0.91238 and 744.8"

Explanation:

In this scenario it is easier to take a person to the water-pool than to transport the people in the air, as the person's strength is increased by water upwards:

f_b \to m \to mg =person \\\\F_B \ in\  air = v\ & air\  g \\\\

               =0.076 \times 1.225 \times 9.8 \\\\ =0.91238 \ N\\\\

F_B \ in \ water = v  \& water \ g \\\\

                    =0.076 \times 1000 \times 9.8\\\\= 744.8 \ N\\

6 0
3 years ago
1. A sample consisting of 1.0 mol CaCO3 (s) was heated to 800oC when it is decomposed. The heating was carried out in a containe
ExtremeBDS [4]
Expansion work against constant external pressure: w=-pex Δ Δ V 3. The attempt at a solution . I tried following that. Because Vf>>Vi, and Vf=nRT/pex, then w=-pex x nRT/pex=-nRT (im assuming n is number of moles of CO2?). 1 mole of CaCO3 makes 1 mole of CO2, so plugging in numbers, I get 8.9kJ, although I dont use the 1 atm pressure at all
6 0
3 years ago
As a diligent physics student, you carry out physics experiments at every opportunity. At this opportunity, you carry a 1.33 m l
deff fn [24]

Answer: 62 μT

Explanation:

Given

Length of rod, l = 1.33 m

Velocity of rod, v = 3.19 m/s

Induced emf, e = 0.263*10^-3 V

Using Faraday's law, the induced emf of a rod can be gotten by the formula

e = blv where,

e = induced emf of the rod

b = magnetic field of the rod

l = length of the rod

v = velocity of the rod. On substituting, we have

0.263*10^-3 = b * 1.33 * 3.19

0.263*10^-3 = b * 4.2427

b = 0.263*10^-3 / 4.2427

b = 0.0000620 T

b = 62 μT

Thus, the strength of the magnetic field is 62 μT

8 0
3 years ago
Read 2 more answers
Wrapping paper is being unwrapped from a 5.0-cm radius tube, free to rotate on its axis. if it is pulled at the constant rate of
lisov135 [29]
So the equation for angular velocity is

Omega = 2(3.14)/T

Where T is the total period in which the cylinder completes one revolution.

In order to find T, the tangential velocity is

V = 2(3.14)r/T

When calculated, I got V = 3.14

When you enter that into the angular velocity equation, you should get 2m/s
5 0
4 years ago
A real power supply can be modeled as an ideal EMF of 60 Volts in series with an internal resistance. The voltage across the ter
lara31 [8.8K]

Answer:

5 ohms

Explanation:

Given:

EMF of the ideal battery (E) = 60 V

Voltage across the terminals of the battery (V) = 40 V

Current across the terminals (I) = 4 A

Let the internal resistance be 'r'.

Now, we know that, the voltage drop in the battery is given as:

V_d=Ir

Therefore, the voltage across the terminals of the battery is given as:

V= E-V_d\\\\V=E-Ir

Now, rewriting in terms of 'r', we get:

Ir=E-V\\\\r=\frac{E-V}{I}

Plug in the given values and solve for 'r'. This gives,

r=\frac{60-40}{4}\\\\r=\frac{20}{4}\\\\r=5\ ohms

Therefore, the internal resistance of the battery is 5 ohms.

5 0
3 years ago
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