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2 years ago

Please help me with part 2. Will give brainliest

Physics

1 answer:

galben [10]2 years ago

8 0

Hi there!

We can use the derived equation to solve:

$t = \sqrt{\frac{2h}{g}}}$ , where:

h = height

g = acceleration due to gravity

Plug in the given values. Remember to CONVERT km to m:

32 km = 32 km * 1000 m / 1 km = 32,000 m

t = √(2(32000)/3.4) ≈ 137.199 sec

Part 2:

Use the derived equation:

vf = √2gh

vf = √(32000)(3.4) = 329.848 m/s

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Answer:

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As the difference between the resistance of voltmeter and the resistance being measured gets reduced the error in the reading of the voltmeter gets increased. This is why we want to have a greater value of voltmeter resistance, ideally infinite so that the corresponding error is minimized.

Lets consider the given scenario,

A voltmeter has 1 MΩ parallel resistance and the resistance of of measuring element is 500 kΩ or 0.5 MΩ

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Now consider the loading effect, when we connect the voltmeter across the 0.5 MΩ resistor they both become parallel so the resistance is

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3 years ago

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3 years ago

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3 years ago

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Volgvan

Answer:

hello your question is incomplete attached below is the complete question

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