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2 years ago

Please help me with part 2. Will give brainliest

Physics

1 answer:

galben [10]2 years ago

8 0

Hi there!

We can use the derived equation to solve:

$t = \sqrt{\frac{2h}{g}}}$ , where:

h = height

g = acceleration due to gravity

Plug in the given values. Remember to CONVERT km to m:

32 km = 32 km * 1000 m / 1 km = 32,000 m

t = √(2(32000)/3.4) ≈ 137.199 sec

Part 2:

Use the derived equation:

vf = √2gh

vf = √(32000)(3.4) = 329.848 m/s

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A 0.10 kg baseball travelling at 40 m s−1 hits straight back to the pitcher at 55 m s−1. The contact time is 0.01 seconds. What

Ilia_Sergeevich [38]

Answer:

1.5 kgms⁻¹

Explanation:

Momentum can be defined as "mass in motion."

The amount of momentum that an object has is dependent upon two factors

mass of the moving object

speed of motiom

when there is a change in the velocity , it creates a change in momentum also

when we consider that we can mathematically show this,In terms of an equation,

Change in momentum (ΔΡ) = m(Δv)

where (Δv) - change in velocity

(Δv) = final velocity - initial velocity

Change in momentum (ΔΡ) = m(Δv)

= 0.1×([55-40])

= 1.5 kgms⁻¹

7 0

3 years ago

The potential difference across a and b is 15 v. determine the electrical charge on the 3 μf capacitor?

Slav-nsk [51]

The potential difference across a and b is 15 v. determine the electrical charge on the 3 μf capacitor will be 45 * $10^{-6}$ C

Capacitance, property of an electric conductor, or set of conductors, that is measured by the amount of separated electric charge that can be stored on it per unit change in electrical potential. Capacitance also implies an associated storage of electrical energy.

Charge (Q) stored in a capacitor is the product of its capacitance (C) and the voltage (V) applied to it. The capacitance of a capacitor should always be a constant, known value. So we can adjust voltage to increase or decrease the cap's charge. More voltage means more charge, less voltage... less charge.

charge = capacitance * voltage

Q = CV

= 3 * $10^{-6}$ * 15 v

= 45 * $10^{-6}$ C

To learn more about capacitance here

brainly.com/question/14746225

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8 0

2 years ago

a mass of 1.00 kg of water at temperature T is poured from a height of 0.100 km into a vessel containing water of the same tempe

Mariana [72]

Answer:

1.34352 kg

Explanation:

$m_w$ = Mass of water falling = 1 kg

h = Height of fall = 0.1 km

$\Delta T$ = Change in temperature = 0.1

c = Specific heat of water = 4186 J/kg K

g = Acceleration due to gravity = 9.81 m/s²

$m_v$ = Mass of water in the vessel

Here the potential energy will balance the internal energy

$m_wgh=m_wc\Delta T+m_vc\Delta T\\\Rightarrow m_v=\dfrac{m_wgh-m_wc\Delta T}{c\Delta T}\\\Rightarrow m_v=\dfrac{m_wgh}{c\Delta T}-m_w\\\Rightarrow m_v=\dfrac{1\times 9.81\times 100}{4186\times 0.1}-1\\\Rightarrow m_v=1.34352\ kg$